Hydrogen fluoride (HF) behaves as a weak acid in aqueous solution. Two equilibria influence which fluorine-containing species are present in solution. HF (aq) + H2O (l) ⇌ H3O+ (aq) + F- (aq) Ka = 6.8 x 10-4 F- (aq) + HF (aq) ⇌ HF2- Kc = 2.6 x 10-1 A. Is fluoride in pH 7.00 drinking water more likely to be present as F− or HF2−? B. What is the equilibrium constant for the following equilibrium? 2 HF(aq) + H2O(?) ⇌ H3O+(aq) + HF2−(aq) C. What are the pH and equilibrium concentration of HF2− in a 0.150 M solution of HF?

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Chapter12: Chemical Equilibrium
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Problem 12.11PAE
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Hydrogen fluoride (HF) behaves as a weak acid in aqueous solution. Two equilibria influence
which fluorine-containing species are present in solution.
HF (aq) + H2O (l) ⇌ H3O+ (aq) + F- (aq) Ka = 6.8 x 10-4
F- (aq) + HF (aq) ⇌ HF2- Kc = 2.6 x 10-1
A. Is fluoride in pH 7.00 drinking water more likely to be present as F− or HF2−?
B. What is the equilibrium constant for the following equilibrium?
2 HF(aq) + H2O(?) ⇌ H3O+(aq) + HF2−(aq)
C. What are the pH and equilibrium concentration of HF2− in a 0.150 M solution of HF?
 
 
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