Hydrogen gas, H2H2, reacts with nitrogen gas, N2N2, to form ammonia gas, NH3NH3, according to the equation 3H2(g)+N2(g)→2NH3(g) Part A How many moles of NH3NH3 can be produced from 16.5 molmol of H2H2 and excess N2N2 How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2. How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3? How many molecules (not moles) of NH3NH3 are produced from 8.25×10−4 gg of H2H2? Express your answer numerically as the number of molecules.

Hydrogen gas, H2H2, reacts with nitrogen gas, N2N2, to form ammonia gas, NH3NH3, according to the equation 3H2(g)+N2(g)→2NH3(g) Part A How many moles of NH3NH3 can be produced from 16.5 molmol of H2H2 and excess N2N2 How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2. How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3? How many molecules (not moles) of NH3NH3 are produced from 8.25×10−4 gg of H2H2? Express your answer numerically as the number of molecules.

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter11: Stoichiometry

Section: Chapter Questions

Problem 9STP

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Part A

How many moles of NH3NH3 can be produced from 16.5 molmol of H2H2 and excess N2N2

How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2.

How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3?

How many molecules (not moles) of NH3NH3 are produced from 8.25×10⁻⁴ gg of H2H2?

Express your answer numerically as the number of molecules.

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