Reaction of hydrogen and nitrogen to form ammonia Hydrogen gas, H2H2, reacts with nitrogen gas, N2N2, to form ammonia gas, NH3NH3, according to the equation 3H2(g)+N2(g)→2NH3(g) Part B How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2. Part C How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3? Part D How many molecules (not moles) of NH3NH3 are produced from 8.25×10−4 gg of H2H2?
Reaction of hydrogen and nitrogen to form ammonia Hydrogen gas, H2H2, reacts with nitrogen gas, N2N2, to form ammonia gas, NH3NH3, according to the equation 3H2(g)+N2(g)→2NH3(g) Part B How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2. Part C How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3? Part D How many molecules (not moles) of NH3NH3 are produced from 8.25×10−4 gg of H2H2?
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter11: Stoichiometry
Section: Chapter Questions
Problem 9STP
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Reaction of hydrogen and nitrogen to form ammonia
Hydrogen gas, H2H2, reacts with nitrogen gas, N2N2, to form ammonia gas, NH3NH3, according to the equation
3H2(g)+N2(g)→2NH3(g)
Part B
How many grams of NH3NH3 can be produced from 2.19 molmol of N2N2 and excess H2H2.
Part C
How many grams of H2H2 are needed to produce 10.02 gg of NH3NH3?
Part D
How many molecules (not moles) of NH3NH3 are produced from 8.25×10−4 gg of H2H2?
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