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- 3. Please complete all parts to the following table:Cocaine (C17H21O4N) is a natural substance found in the leaves of the coca plant, which has been used for centuries as a local anesthetic and stimulant. Illegal cocaine arrives in the USA either as a pure compound or as the hydrochloride salt (C17H21O4NHCl). At 25oC, the salt is very soluble in water (2.50 kg/L), but pure cocaine is much less so (1.70 g/L). What is the maximum amount of salt (in gram) that can dissolve in 50.0 mL of water? [1 mark.] When a 25 mL aqueous solution that contains 62.50 g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water (in liters) is needed additionally to dissolve the formed pure cocaine? Round your final answer off to two decimal points. C17H21O4NHCl(aq) + NaOH(aq) → C17H21O4N(aq) + H2O(l) + NaCl(aq)Group A: solution conductivity (MS) NaCl 6594 CaCl2 13188 AlCl3 16311 Group B: solution conductivity (MS) HCl 21809 Hc2H3O2 639 H3PO4 8805 For H3PO4, does the subscript "3" of hydrogen in this formula seem to result in additional ions insolution as it did for AlCl3in Group A? Explain.
- Cocaine (C₁₇H₂₁O₄N) is a natural substance found in cocaleaves, which have been used for centuries as a local anestheticand stimulant. Illegal cocaine arrives in the United States eitheras the pure compound or as the hydrochloride salt(C₁₇H₂₁O₄NHCl). At 25C, the salt is very soluble in water(2.50 kg/L), but cocaine is much less so (1.70 g/L). (a) Whatis the maximum amount (in g) of the salt that can dissolve in50.0 mL of water? (b) If the solution in part (a) is treated withNaOH, the salt is converted to cocaine. How much additionalwater (in L) is needed to dissolve it?For each of the answers in Problem 60, state whether the species is polar or nonpolar.Cyclopropane is an interesting hydrocarbon. Instead of havingthree carbons in a row, the three carbons form a ring, asshown in this perspective drawing (see Figure 2.18 for a priorexample of this kind of drawing):Cyclopropane was at one time used as an anesthetic, but itsuse was discontinued, in part because it is highly flammable.(a) What is the empirical formula of cyclopropane? Howdoes it differ from that of propane? (b) The three carbon atomsare necessarily in a plane. What do the different wedgesmean? (c) What change would you make to the structureshown to illustrate chlorocyclopropane? Are there isomers ofchlorocyclopropane?
- Cyclopropane is an interesting hydrocarbon. Instead of havingthree carbons in a row, the three carbons form a ring, asshown in this perspective drawing (see Figure 2.18 for a priorexample of this kind of drawing): Cyclopropane was at one time used as an anesthetic, but its use was discontinued, in part because it is highly flammable.(a) What is the empirical formula of cyclopropane? Howdoes it differ from that of propane? (b) The three carbon atomsare necessarily in a plane. What do the different wedgesmean? (c) What change would you make to the structureshown to illustrate chlorocyclopropane? Are there isomers ofchlorocyclopropane?Cocaine(C17H21O4N) is a natural substance found in the leaves of the coca plant, which has been used for centuries as a local anesthetic and stimulant. Illegal cocaine arrives in the USA either as a pure compound or as the hydrochloride salt(C7H21O4NHCl). At 25 degrees celsius, the salt is very soluble in water(2.59kg/L), but pure cocaine is much less so(1.70g/L) a. What is the maximum amount of salt in grams that can dissolve in 50.0mL of water? b. When a 25mL aqueous solution that contains 62.50 g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water in liters is needed additionally to dissolve the formed pure cocaine,The attractive force between two ions in Na20, Fc is 8.64x10-9N. What is the bond length a0 (in nm) given that valence of the charged Na+ is Z1=+1, for O-, is Z2 =-2, the charge of a single electron q is 0.16x10-18 C and the proportionality constant k0=9x109 V.m/C? Note that K=k0(Z1q)(Z2q) and that 1 V.C = 1 J.
- Consider following reaction: HgO (s) -> Hg(l) + ½ O2 (g) Delta H = +90.7 kj/mol. What quantity of heat in kj/mol is required to produce one mole HgO? Write your answer without units. Given the following data 2ClF(g) + O2(g) --> Cl2O(g) + F2O (g) Delta H= 167.4 kJ I 2ClF3(g) + 2O2(g) --> Cl2O(g) + 3F2 O (g) Delta H= 341.4 kJ II 2 F2(g) + O2(g) ---> 2F2O (g) Delta H= -43.4 kJ III Calculate the delta H in kJ for below reaction: ClF(g) + F2(g) ---> ClF3(g)name the following compounds. I need part K, L, SComplete the following using only what is on this page.
