(i) Pt(s) + 2 NH3(aq) + 2 CI ( (aq) cis-[PtCl₂(NH3)2](aq) + 2 e¯ E° = 0.274 V The likely cathodic reaction is the evolution of H₂ gas from water as shown in the equation below. (ii) 2 H₂O +2 e H₂(g) + 2OH(aq) E° = -0.828 V The given E° values above are at 25 °C.
(i) Pt(s) + 2 NH3(aq) + 2 CI ( (aq) cis-[PtCl₂(NH3)2](aq) + 2 e¯ E° = 0.274 V The likely cathodic reaction is the evolution of H₂ gas from water as shown in the equation below. (ii) 2 H₂O +2 e H₂(g) + 2OH(aq) E° = -0.828 V The given E° values above are at 25 °C.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter19: The Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 73QRT
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Question
Rose was studying the electric field effect on bacterial growth when he unknowingly carried out an anodic reaction on the platinum electrode that led to the discovery of the anticancer drug cisplatin, cis-[PtCl2(NH3)2].
> Determine the formation constant (Kf) of cisplatin at 25 °C.
 + 2 e¯
E° = 0.274 V
The likely cathodic reaction is the evolution of H₂ gas from water as shown in the equation below.
(ii) 2 H₂O +2 e
H₂(g) + 2 OH(aq)
E° = -0.828 V
The given E° values above are at 25 °C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe59a83d7-b547-4991-850e-a58bc35a2549%2F4a99a1a9-7d8f-4751-8641-ca1c278a6944%2Fwk1g8a_processed.png&w=3840&q=75)
Transcribed Image Text:(i) Pt(s) + 2 NH3(aq) + 2 CI (aq) ⇒ cis-[PtCl2(NH3)2](aq) + 2 e¯
E° = 0.274 V
The likely cathodic reaction is the evolution of H₂ gas from water as shown in the equation below.
(ii) 2 H₂O +2 e
H₂(g) + 2 OH(aq)
E° = -0.828 V
The given E° values above are at 25 °C.
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