(c) A vacuum tube of semiconductor bar with = 2.2 (S/m) has a radius of r = 5 mmand length, 1 = 10 mm is subjected to an electric field, E = 25 (mV/m) andHe=0.13 (m²/V.s), h = 0.15 (m²/V.s), N₂ = 2.0 x 10¹6 electrons/m³, andNh=2.0 x 10¹6. Compute the following:[Tiub vakum bar semikonduktor dengan o = 2.2 (S/m) mempunyai jejari, r = 5 mm dan panjang,1 = 10 mm adalah tertakluk kepada medan elektrik, E = 25 (mV/m) dan He = 0.13 (m²/V.s),Hh = 0.15 (m²/V.s), N₂ = 2.0 x 10 electrons/m³, and N₁ = 2.0 x 106. Kirakan yang berikut:](i)The free electron and hole volume charge density[Electron bebas dan isipadu ketumpatan cas lubang](ii) The current, I flowing in the bar[Arus, I yang mengalir pada bar](iii) The drift velocities He and h[Halaju hanyutan dan μ₁](iv) The resistance of the bar[Rintangan pada bar](v) The power dissipated in the bar[Kuasa yang dilesapkan pada bar]

In the following problem for the vacuum tube of semiconductor, σ=2.2 S/m Radius, r=5 mm Length, l=10…

(i) The free electron and hole volume charge density [Electron bebas dan isipadu ketumpatan cas lubang] (ii) The current, I flowing in the bar [Arus, I yang mengalir pada bar] (iii) The drift velocities and h [Halaju hanyutan μ, dan μ₁] (iv) The resistance of the bar [Rintangan pada bar] (v) The power dissipated in the bar [Kuasa yang dilesapkan pada bar]

(i) The free electron and hole volume charge density [Electron bebas dan isipadu ketumpatan cas lubang] (ii) The current, I flowing in the bar [Arus, I yang mengalir pada bar] (iii) The drift velocities and h [Halaju hanyutan μ, dan μ₁] (iv) The resistance of the bar [Rintangan pada bar] (v) The power dissipated in the bar [Kuasa yang dilesapkan pada bar]

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 17CQ: Under electrostatic conditions, the excess charge on a conductor resides on its surface. Does this...

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