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i.e. P(>50) = P(X-9 olun But we know that Z=-4 oi√n - →210,1) = P(Z > Sone rivn from given data, ) = 50-4 61√n = P(Z > 50-65-33 31.59/√7 1.0.9995 = 0.9005 as 1) = = P(Z -1.2839) P(Z > 1.2839) = 1- P(Z <1.2839) P(X >50) = by CLT, 0.9005

i.e. P(>50) = P(X-9 olun But we know that Z=-4 oi√n - →210,1) = P(Z > Sone rivn from given data, ) = 50-4 61√n = P(Z > 50-65-33 31.59/√7 1.0.9995 = 0.9005 as 1) = = P(Z -1.2839) P(Z > 1.2839) = 1- P(Z <1.2839) P(X >50) = by CLT, 0.9005

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.4: Graphs Of Logarithmic Functions
Problem 60SE: Prove the conjecture made in the previous exercise.
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PLEASE MAKE A NORMAL DISTRIBUTION CURVE FOR THIS. DIGITAL ONLY NOT HANDWRITTEN

i.e. P(50) = P(x-4 Z=-4 01√n = But we know that →21011) = P(Z > Sond = olun = P(Z > ) from given data, 50-65-33 ') 31.5917 50-4) 6√n 1-0.9995 = 0.9005 as P(X >50) = PIZY -1.2839) P(Z > 1.2839) = 1~P(Z <1.2839) by CLT, 888, 0.9005
Transcribed Image Text:i.e. P(50) = P(x-4 Z=-4 01√n = But we know that →21011) = P(Z > Sond = olun = P(Z > ) from given data, 50-65-33 ') 31.5917 50-4) 6√n 1-0.9995 = 0.9005 as P(X >50) = PIZY -1.2839) P(Z > 1.2839) = 1~P(Z <1.2839) by CLT, 888, 0.9005
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