Identify the strongest reducing agent based on the following half- reactions. 2+ +1.22 V MnO₂ (s) + 4H* (aq) + 2e → Mn²(aq) + 2H₂O(1) Hg₂SO4(s) + 2e → 2Hg(1) + SO4² (aq) +0.61 V -0.95 V SnO₂(s) + 2H₂O0+ 4e → Sn(s) + 4OH(aq) Cr(OH)3(s) + 3e Cr(s) + 3OH (aq) -1.48 V → Cr Mn02 Hg2SO4 Sn Hg

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.95QE
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Identify the strongest reducing agent based on the following half-
reactions.
2+
+1.22 V
→
Mn (aq) + 2H₂O(1)
+0.61 V
MnO₂(s) + 4H* (aq) + 2e-
Hg₂SO4(s) + 2e → 2Hg(1) + SO4 (aq)
SnO₂(s) + 2H₂O0+ 4e → Sn(s) + 4OH(aq)
Cr(OH)3(s) + 3e → Cr(s) + 3OH(aq)
-0.95 V
-1.48 V
Cr
Mn02
Hg2SO4
Sn
Hg
Transcribed Image Text:Identify the strongest reducing agent based on the following half- reactions. 2+ +1.22 V → Mn (aq) + 2H₂O(1) +0.61 V MnO₂(s) + 4H* (aq) + 2e- Hg₂SO4(s) + 2e → 2Hg(1) + SO4 (aq) SnO₂(s) + 2H₂O0+ 4e → Sn(s) + 4OH(aq) Cr(OH)3(s) + 3e → Cr(s) + 3OH(aq) -0.95 V -1.48 V Cr Mn02 Hg2SO4 Sn Hg
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