If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
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Chapter3: Calculations With Chemical Formulas And Equaitons
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Problem 3.120QP: You perform a combustion analysis on a 255 mg sample of a substance that contains only C, H, and O,...
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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol
Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol
Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
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