If a 2.0 g sample of water at 5.0° C absorbs 21.8 of heat energy, what will the temperature of the sample be raised by?

Q: Calculate the amount of heat energy (in joules) needed to rase the temperature of 12.50 g of water…

A: Heat released or absorbed by an object is calculated using law if calorimetry. This law states that,…

Q: A 32.06 g sample of a substance is initially at 25.4 °C. After absorbing 1067 J of heat, the…

A: Mass of sample = 32.06 g  Initial temperature (T1) = 25.4 °C  Final temperature (T2) = 132.2 °C…

Q: A 36.45 g sample of a substance is initially at 28.4 °C. After absorbing 1041 J of heat, the…

A: The mass of the substance is = 36.45 g The increase in the temperature of the substance is =…

Q: A 45.61 g sample of a substance is initially at 24.6 °C. After absorbing 2495 J of heat, the…

A: Mass of sample m = 45.61 gramInitial temperature T1 = 24.6 °CFinal temperature T2 = 119.5 °CHeat…

Q: A 59.55 g sample of a substance is initially at 25.6 °C. After absorbing 1881 J of heat, the…

A: Given:             Q = 1881J            Mass (m) = 59.55g = 0.0595Kg Temperature(T1) = 25.6°C = 25.6…

Q: Two substances, A & B, have equal masses. If each absorbs 25 Joules of energy, and the temperature…

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Q: How much heat (in kJ) will be absorbed by a 31.5 g piece of aluminum (specific heat = 0.930 J/g･°C)…

A:

Q: How much heat (in kJ) will be absorbed by a 79.1 g piece of aluminum (specific heat = 0.930 J/g･°C)…

A: Given: Mass of Al piece = 79.1 gSpecific heat of Al = 0.930 J/g.°CInitial temperature = 23.0 °CFinal…

Q: A 5.34g sample of aluminum at 23oC absorbs 170 J of heat.  What is the new temperature of the…

A: According to the law of calorimetry Heat absorbed by a substance depends on mass of the substance,…

Q: A 37.15 gram sample of copper (specific heat, 0.385 J/g•°C) with an initial temperature of 95.8°C is…

A: We know that, according to the law of conservation of heat energy, energy gained or loss by the…

Q: How much heat (in J) is evolved or absorbed when a 36.2 g sample of aluminum (specific heat = 0.900…

A: In this question gven data , m=36.2gheat capacity=0.900J/(g K)∆T =T2 -T1T2=87.5°C=273+87.5=360.5KT1…

Q: How much heat will be absorbed by a 96.7 g piece of aluminum (specific heat = 0.930 J/g·°C) as it…

A: To solve this problem we will use the formula  Q = mC∆T  Where ,  Q = heat absorbed  m = mass of…

Q: How much heat (in J) is evolved or absorbed when a 35.1 g sample of ethanol (specific heat = 2.46…

A: specific heat capacity is the amount of heat required to raise the temperature of 1 Kg of a…

Q: How much heat will be absorbed by a 96.7 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A: Given: Mass of aluminum=96.7 g Temperature change, ∆T=(67.0-23.0)°C=44 °C The heat needed q =? J…

Q: A 500—g iron rod is cooled from 90°C to 30°C. How much is the amount of heat released bythe metal?…

A: C. 13.5 kJ Given that Amount of iron rod m = 500 g Initial temperature of iron rod T1 = 90°C Final…

Q: How to calculate the experimental value for the latent heat of fusion of water. 1969.4 cal heat…

A: Latent heat of fusion is the amount of heat required to melt 1 mol or ice at its melting…

Q: A 100.0-g bar of gold is heated from 25 °C to 50 °C during which it absorbs 323 J of heat. Assume…

A: Specific heat capacity (s) :- The amount of heat absorbed by one gram of a substance to increase…

Q: If 40.5 J of heat is added to a 15.4 g sample of silver, how much will the temperature increase by?…

A: The amount of heat required to raise the temperature of a substance by one degree Celsius is called…

Q: It takes 1.25 kJ of energy to heat a certain sample of pure silver from 12.0∘C to 15.2∘C. Calculate…

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Q: Calculate the heat change when 366 g of mercury (specific heat = 0.139 J/g.°C) cools from 77.0 °C to…

A:

Q: How much heat will be absorbed by a 85.5 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A: The amount of heat ('q') that is required to raise the temperature of a sample of mass 'm' having…

Q: A 46.78 g sample of a substance is initially at 26.6 °C. After absorbing 2893 J of heat, the…

A:

Q: How much heat is released when the temperature of an 8.21 g sample of gold decreases from 87.9 oC to…

A: q = mc∆T  q is the amount of heat energy released or absorbed m is the mass of substance  c is the…

Q: An 6.11 g sample of calcium carbonate [CaCO 3 (S)] absorbs 84J of heat, upon which the temperature…

A:

Q: To treat a burn on his hand, a person decides to place an ice cube on the burned skin. The mass of…

A:

Q: Which of the following is/are TRUE for an endothermic process in an open or closed system? I. The…

A: We have to tell which statement is true.

Q: A 21.74 g sample of a substance is initially at 24.4 °C. After absorbing 2903 J of heat, the…

A: A numerical problem based on thermodynamics that is to be accomplished.

Q: A 57.60 g sample of a substance is initially at 22.6 °C. After absorbing 2787 J of heat, the…

A: Given  m = 57.60 g T1 = 22.6°C T2 = 182.8°C Q = 2787 J Specific heat of substances(c)=?

Q: How much heat will be absorbed by a 65.9 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A: Heat in kilojoules can be calculated using the specific heat capacity, temperature difference and…

Q: How much heat (in cal) is needed to heat a container of water (with a mass of 5 kg) (specific heat…

A: Given, Note: 1Kg = 1000 g Mass of water (m) = 5 Kg = 5000 g Specific heat capacity of water (Cp) =…

Q: a 25.31 g sample of a substance is initially at 23.9 °c. after absorbing 2317 j of heat, the…

A:

Q: A 100.0-g bar of gold is heated from 25 °C to 50 °C during which it absorbs 323 J of heat. Assume…

A: Given, the mass of gold bar m =100.0 ginitial temperature T1 =25 °C =(25+273)K =298 Kfinal…

Q: Calculate the energy required (q) to heat 28.6 g of water from 22.0 °C to 78.3 °C. (specific heat of…

A:

Q: How much heat (in kJ) will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g•°C)…

A: We know that   heat energy is given by     q = m* C* ΔT Given that   Mass of Al = 50.3 g   specific…

Q: 1. A 1.50 kg sample of vanadium (specific heat = 0.119 J/g°C) is heated to 85.0°C then placed in a…

A: Consider Tf be the final temperature of the metal and water. The mass of vanadium is 1.50 kg or 1500…

Q: How much heat will be absorbed by a 59.9 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A:

Q: How much heat will be absorbed by a 33.9 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A: Heat absorbed by a body = mC∆t where m= mass of the body C= specific heat of the body ∆t= Change of…

Q: How much heat (in kJ) will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g･°C)…

A: Since ,  Q = m c ∆ T                    where ,                                   Q = Heat…

Q: What is the new temperature of the sample?

A: q = mc∆T  q is the amount of heat energy absorbed m is the mass of substance  c is the specific heat…

Q: How much heat is involved when an 8.50 kg copper is heated from 25 °C to 1000 °C? Specific eat of…

A: We have to predict the heat involved in raising the temperature.

Q: How much heat will be absorbed by a 69.5 g piece of aluminum (specific heat = 0.930 J/g･°C) as it…

A:

Q: How much heat (in kJ) will be absorbed by a 75.9 g piece of aluminum (specific heat = 0.930 J/g･°C)…

A:

Q: A 25.09 g sample of a substance is initially at 24.0 °C. After absorbing 2121 J of heat, the…

A: Interpretation- To determine the specific heat of the substance for  25.09 g sample of a substance…

Q: In an experiment designed to measure the heat of fusion of ice, 25 grams of ice at 0oC is dropped…

A: Given: Mass of hot water = 200 g. Initial temperature of water and calorimeter = 30.0 oC Mass of…

Q: If 67.2 J of heat is added to a 24.6 g sample of silver, how much will the temperature increase by?…

A: Answer:- This question is answered by using the simple concept of calorimetry which involves the…

Q: A 55 kg block of metal has an original temperature of 15.0°C and 0.45 J/g°C. What will be the final…

A: m = 55 kg = 55000 g  Ti = 15°C  c = 0.45 J/g.°C q = 450 J  Tf = ?

Q: A 52.76 g sample of a substance is initially at 28.4 °C. After absorbing 1985 J of heat, the…

A: In given question use formula  q = mc∆T  Given : q = 1985 J  m = 52.76 g  ∆T = 133.4 - 28.4 = 105 °C…

Q: 35.19 g sample of a substance is initially at 27.1 °C. After absorbing 1533 J of heat, the…

A: The heat absorbed or released by a substance is guided by its specific heatthe relation between heat…

Q: specific heat

A:

Q: What is specific heat and what does it measure? How is specific heat determined? What data is…

A: Given : To define specific heat capacity and find out its importance.

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.    

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.