If a section of an electric circuit is as shown, then applying Kirchhoff's first law gives:12Is0 20O h + l3 + Is = l2 + l4Oh+2+l4+l3 = I5Oh+3+l4 12 + Ish+2+ Is l3 + l4O h = 12 + 13 + l4 + I5Clear my choice

According to question we need to find kirchhoff s law in a circuit.

If a section of an electric circuit is as shown, then applying Kirchhoff's first law gives: 12 Is inillm 020 O h+ l3 + Is = l2 + l4 Oh+2+l4+I3 = I5 Oh+3+l4 12 + Is h+2+ Is l3 + l4 O h = 12 + l3 + l4 + 15 Clear my choice

If a section of an electric circuit is as shown, then applying Kirchhoff's first law gives: 12 Is inillm 020 O h+ l3 + Is = l2 + l4 Oh+2+l4+I3 = I5 Oh+3+l4 12 + Is h+2+ Is l3 + l4 O h = 12 + l3 + l4 + 15 Clear my choice

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter14: Inductance

Section: Chapter Questions

Problem 53P: For the circuit shown below, =20V , L = 4.0 mH, and R = 5.0 . After steady state is reached with S1...

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Question

If a section of an electric circuit is as shown, then applying Kirchhoff's first law gives:
12
Is
0 20
O h + l3 + Is = l2 + l4
Oh+2+l4+l3 = I5
Oh+3+l4 12 + Is
h+2+ Is l3 + l4
O h = 12 + 13 + l4 + I5
Clear my choice

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