If a student dilutes 16.34 mL of 2.75 M HCl to 25.00 mL, what is the concentration of the resulting solution

Q: In the laboratory you dilute 4.23 mL of a concentrated 12.0 M hydroiodic acid solution to a total…

A: Given  Initial Volume ( V1 )             = 4.23 mL  Initial Concentration ( M1 ) = 12 M  Final…

Q: A NaF(aq) solution (solution 2) is 9.20% by mass in NaF. Solution 2 has a density of 1.05 g/mL. 415…

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Q: calculate the concentration of a solution when a 15 mL sample of 6 M acetis acid solution is diluted…

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Q: In the laboratory a student combines 31.8 mL of a 0.232 M sodium sulfate solution with 24.7 mL of a…

A: Number of moles of solute devided by volume of solution in liter is known as molarity.

Q: What is the molarity of the new NaOH solution?

A: Initial no. Of moles of NaOH = 6×7 = 42mmoles  New volume, = 400mL  Hence Molarity = no. Of…

Q: A chemist places 2.6428 g of NaCl in a 100 mL volumetric flask and adds water to the mark and calls…

A: The solution is given below -

Q: A chemist places 1.5999 g of NaCl in a 100 mL volumetric flask and adds water to the mark and calls…

A: In given problem, they asked for concentration of Na2SO4 and it is given as NaCl. So it will be…

Q: In the laboratory, a student adds 48.0 mL of water to 14.6 mL of a 0.624 M nitric acid solution.…

A: Given values, N1= 0.624 M V1= 14.6mL N2=?? V2= 14.6+48.0 = 62.6 mL

Q: You have 15 mL of a 0.25 M NaCl(aq) solution. What volume should you dilute it to in order to obtain…

A: Given: The initial volume (V1) of NaCl (sodium chloride) solution is 15 mL The initial molarity (M1)…

Q: In the laboratory, a student dilutes 22.9 mL of a 11.9 M nitric acid solution to a total volume of…

A: Moles of solute remain constant during dilution. Moles of solute = molarity x volume of solution…

Q: 4.27 mL of a 0.283 M NAOH solution reacts completely with 4.70 mL of HCI solution according to the…

A: Given :-              Molarity of NaOH solution =0.283 M               Volume of HCl solution =4.70…

Q: In the laboratory, a student dilutes 27.2 mL of a 8.33 M hydroiodic acid solution to a volume of…

A: hydroiodic acid solution ( HI ) Initial volume = V1 = 27.2 mL Initial Concentration = M1 = 8.33 M…

Q: A solution of HCl was prepared from a stock solution as follows: 50.00 mL of stock solution was…

A: Given: Volume of stock solution used = 50.00 mL Volume of dilution A prepared = 250.0 mL Volume of…

Q: In the laboratory, a student adds 44.1 mL of water to 12.1 mL of a 0.577 M nitric acid solution.…

A: Provided initial Molarity(M1)=0.577M Let final Molarity = M2    (say) Initial volume of nitric acid…

Q: When 234 mL of water are added to 11.9 mL of 16 M HCI, what will be the new molarity? i M HCI

A: Given: Volume=11.9 mL=11.9×10-3 LMolarity=16 MVolume added=234 mL=234×10-3 L To find: Final molarity…

Q: 350. mL of a 0.255 M zinc chloride solution is diluted to a volume of 785 mL, what is the molarity…

A: Given that: Initial molarity of the solution = 0.255 M Initial volume of the solution = 350 mL…

Q: A student pipets 11 mL of a 0.0155 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes…

A: Given,

Q: If 203 mL of water is added to 5.00 mL of 4.16 M KCI solution, what is the concentration of the…

A: • The values provided in the question are:-  i) Initial volume of KCl solution, V1 = 5.00 mL  ii)…

Q: It is desired to prepare 0.500 L of a 0.125 M solution of NaCI from a 1.00 M stock solution. How…

A: molarity is defined as no of moles of solute devided by volume of solution in liter

Q: A student is asked to prepare 250 mL of a 0.0104 M NaCl solution. The student found a stock bottle…

A: Given: A student has to prepare 250 mL of 0.0104 M NaCl solution using 34.7 mL of 0.0723 M NaCl…

Q: If exactly one molecule of solute is present in 1.001.00 L of solution, what is the concentration of…

A: We know ; 1 mol of Solute = 6.022 × 10²³ Molecules   * Molarity of Solution = Moles of Solute /…

Q: This question has two parts: A student is trying to prepare 500. mL of 6.0 M sodium hydroxide, NaOH,…

A: molarity =w/M ×1000/v in ml W=weight of solute M=molar mass of solute   NaoH molar mass 40 g /mol

Q: What is the molarity of the resulting solution when 300. mL of a 0.600 M aqueous solution is diluted…

A: Given :-  Initial concentration (M1) = 0.600 M  Initial volume (V1) = 300 mL  Final volume (V2) =…

Q: What volume of 0.218 M KMnO4 solution is needed to prepare 503. mL of 0.0151 M KMnO4? Enter your…

A: The equation is, M1V1 = M2V2

Q: In the laboratory a student combines 46.6 mL of a 0.307 M iron(III) fluoride solution with 22.4 mL…

A: GIVEN: The Volume of Iron(III) Fluoride = 46.6 mL The concentration of Iron(III) Fluoride =0.307 M…

Q: A 22.7-g sample of HF is dissolved in enough water to give 2.0 × 102 mL of solution.  What is the…

A: Given: weight of HF=22.7gvolume of solution = 2.0×102mlconcentration of a solution is defined as…

Q: a forensic chemist prepares 290.0 mL of a 0.649 M solution from a 4.04 M stock solution. what volume…

A: Molarity is the unit of concentration of a solution, and its unit is mol/L. It is defined by the…

Q: You wish to make a 0.338 M hydrochloric acid solution from a stock solution of 12.0 M hydrochloric…

A: Concentrated solutions upon addition of water gets diluted to lower concentrations. The dilution of…

Q: A solution of NaCl is prepared by dissolving 1.75 g NaCl in enough water to make 100.00 mL of…

A:

Q: If 255 mL of water is added to 325 mL of a 0.477 M solution, what is the molarity of the new…

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Q: In the laboratory, a student dilutes 18.8 mL of a 11.5 M nitric acid solution to a total volume of…

A: V1 = 18.8 mL = 0.0188 L  M1 = 11.5 M  V2 = 200 mL = 0.200 L  M2 = ?

Q: A student needs to make 250 mL of 1.4 M Fe(NO3)3 by dilution. How many milliliters of a 5.0 M…

A: Given data:  Initial molarity of Fe(NO3)3 (M1) is 5.0 M The final volume of Fe(NO3)3 (V2) is 250 mL.…

Q: In the laboratory, a student dilutes 18.4 mL of a 6.23 M hydrobromic acid solution to a total volume…

A: Given information: C1 = 6.23 M V1 =18.4 mL V2 = 200.0 mL

Q: What is the concentration of the diluted solution?

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Q: A student weighs out a 3.06g sample of MgBr2, transfers it to a 135mL volumetric flask, adds enough…

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Q: You wish to make a 0.315 M perchloric acid solution from a stock solution of 12.0 M perchloric acid.…

A: Given, the concentration of stock solution =12.0 Mconcentration of diluted solution =0.315 Mvolume…

Q: A student pipets 18 mL of a 0.0459 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes…

A: Given  Initial Volume of solution ( V1 ) = 18 mL  Molarity ( M1 ) = 0.0459 M  Final Volume of…

Q: In the laboratory a student combines 21.9 mL of a 0.211 M iron(II) iodide solution with 30.0 mL of…

A: Given- Concentration of iron (||)iodide solution= 0.211M Volume of iron (||) iodide solution =21.9…

Q: Suppose you need to prepare 138.6 mL of a 0.426 M aqueous solution of NaCl. what mass of grams in…

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Q: A student uses a pipette to dilute 1.00 mL of a standard iron solution to 50.0 mL. If the µg what…

A:

Q: To what volume should you dilute 35 mL of a 13 M stock HCl solution to obtain a 0.600 M HCl…

A: Given :-  initial concentration = 13 M  initial volume = 35 mL  final concentration = 0.600 M  To…

Q: A solution of highly concentrated Sulphuric acid having Molarity 18 M of volume 25 ml was diluted to…

A: •Molarity = moles of solute / volume of solution in litres  • In dilution moles of solute remains…

Q: What is the molar concentration of a solution consisting of 0.173 g NaCl in 500. mL?

A: Weight of NaCl= 0.173g Volume=500mL =0.500 L       (1L = 1000 ml) Molar concentration=?

Q: What is the molarity of a solution prepared using the given amount of solute and total volume of…

A: Molarity is the concentration of no. Of moles of solute in 1 L of solution. Molarity= moles of…

Q: A student weighs out a 2.76 g sample of NaOH , transfers it to a 500. mL volumetric flask, adds…

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Q: A student weighs out 3.23 g of KBr, transfers it to a 125. mL volumetric flask, adds enough water to…

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Q: If 200. mL of water is added to 10.0 mL of 4.00 M NaCI solution, what is the concentration of the…

A: Given data is as follows: The initial concentration of NaCl M1 = 4.00 M The initial volume of the…

Q: Consider a solution prepared by combining 45.0 g of BaCl2 with enough water to prepare a 750.0 mL of…

A: Given: Volume of solution = 750 mL = 0.750 L Mass of BaCl2 = 45.0 g Molar mass of BaCl2 = 208.23…

Q: A student needs to dilute a 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution to make 89.089.0 mL of 0.22 M…

A: For preparing the working solutions we use dilution formula. M1V1=M2V2M1=molarity of stock…

Q: How many grams of solute are present in 155 mL155 mL of 0.280 M KBr

A: Solution:- Given => 155 mL of 0.280 M KBr.  Volume of solution = 155 mL = 0.155 L Molarity =…