A student needs to dilute a 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution to make 89.089.0 mL of 0.22 M Pb(NO3)20.22 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution that is needed.
A student needs to dilute a 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution to make 89.089.0 mL of 0.22 M Pb(NO3)20.22 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution that is needed.
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 24QAP: Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the...
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A student needs to dilute a 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution to make 89.089.0 mL of 0.22 M Pb(NO3)20.22 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.36 M Pb(NO3)20.36 M Pb(NO3)2 solution that is needed.
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