If an object is thrown upward with an initial velocity of 256 tusecond, then its height after t seconds is given by the following equation. h= 256t - 321? a. Find the maximum height attained by the object. b. Find the number of seconds it takes the object to hit the ground.

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If an object is thrown upward with an initial velocity of 256 ft/second, then its height after t seconds is given by the following equation.
h= 256t – 3212
a. Find the maximum height attained by the object.
b. Find the number of seconds it takes the object to hit the ground.
a. The maximum height attained by the object is 512 feet.
b. The number of seconds it takes the object to hit the ground is 8 seconds.
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Transcribed Image Text:If an object is thrown upward with an initial velocity of 256 ft/second, then its height after t seconds is given by the following equation. h= 256t – 3212 a. Find the maximum height attained by the object. b. Find the number of seconds it takes the object to hit the ground. a. The maximum height attained by the object is 512 feet. b. The number of seconds it takes the object to hit the ground is 8 seconds. (1) More Enter your answer in each of the answer boxes. ?
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