If the beam is subjected to an internal moment of M = 3 kN.m Determine: i. The maximum compressive stress in the beam The maximum tensile stress in the beam i. Also, sketch the bending stress distribution on the cross section 100 mm 25 mm 25 mm M. 75 mm 25 mm 75 mm 75 mm 25 mm
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- The T-shaped beam shown above is supporting a concentrated load P at its free end. The beam has an allowable bending stress of ?????? = 250 MPa and an allowable shear stress of ?????? = 100 MPa. a) Determine the distance to the neutral axis (?̅), second moment of area (?), and the section modulus (?) of the cross-section.b) Draw the shear force diagram (SFD) and bending moment diagram (BMD) of the beam. On your diagrams, express the values of shear and moment in terms of the applied load P.c) Determine the maximum value of P such that bending failure will not occur.d) Determine the maximum value of P such that shear failure will not occur.e) Based on your answers to (c) and (d), what is the maximum load P that can be applied to the beam? Is this beam bending or shear governed?The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,867,500 mm4. Determine the horizontal shear stress at point H, which is located L = 17 mm below the centroid. 58.9 MPa 42.7 MPa 39.6 MPa 35.2 MPa 31.2 MPaSince the beam M in the figure is under the effect of simple bending moment, calculate the bending stress and shear stress values at the A, B and C points. h = 400mm b = 140mm and M = 150KNm
- Given: Maximum positive shear = 3960 N Maximum negative shear = 5640 N Maximum positive moment = 20700 N-m Maximum negative moment = 2400 N-m Location of maximum shear from the left end of beam = 19 m Location of maximum moment from the left end of beam = 14 m Determine the maximum bending stress (in MEGAPASCALS on the beam) given the cross-section on figure. Exercise caution in choosing the value of "c". (Be it known obviously that for beams with irregular cross-sections, Ctop ≠ Cbottom) Note: Measurements in figure is in millimeters. Kindly Draw the Shear and Moment Diagram or FBD if necessary. Compute for all of the necessary elements, Include the proper units, use the proper formula and round-off all the answers and final answers to 2 decimal places.Find the length that a solid steel shaft of diameter d = 13 mm must have for its ends to rotate 90º with respect to each other. An allowable shear stress of Sy ’= 713.8 kg / cm2, and G = 8.1573x10 ^ 5 kg / cm2 must not be exceededConsider a 130-mm-long segment of a simply supported beam. The internal bending moments on the left and right sides of the segment are 55 kN-m and 60 kN-m, respectively. The cross-sectional dimensions of the flanged shape are shown in the accompanying figure. Assume b1 = 165 mm, b2 = 40 mm, b3 = 290 mm, d1 = 65 mm, d2 = 240 mm, d3 = 65 mm. Determine the maximum horizontal shear stress in this segment of the beam.
- Given: Maximum positive shear = 387.50 kN Maximum negative shear = 602.50 kN Maximum positive moment = 1970.65 kN-m Maximum negative moment = 1480 kN-m Location of maximum shear from the left end of beam = 22 m Location of maximum moment from the left end of beam = 15.23 m Determine the maximum bending stress (in MEGAPASCALS on the beam) given the cross-section on figure. Exercise caution in choosing the value of "c". (Be it known obviously that for beams with irregular cross-sections, Ctop ≠ Cbottom) Note: Measurements in figure is in millimeters. Kindly Draw the Shear and Moment Diagram or FBD if necessary. Compute for all of the necessary elements, Include the proper units, use the proper formula and round-off all the answers and final answers to 2 decimal places.H1. A rectangular beam of 100mm wide and 150mm deep is subjected to Shear force of 30KN, Determine ratio of Maximum shear stress to Average shear stress. Derive the equation which is used to find out the shear stress.1-10. A bar of variable cross section, held on the left, is subjected to three forces, P =4 kN, P, = -2 KN, and P, = 3 kN, as shown in the figure. On two separate diagrams, plot the axial force and the axial stress along the length of the bar. Let A1, = 200 mm, A2, = 100mm², and A3, = 150 mm".
- Consider a 155-mm-long segment of a simply supported beam. The internal bending moments on the left and right sides of the segment are 75 kN-m and 79 kN-m, respectively. The cross-sectional dimensions of the flanged shape are shown in the accompanying figure. Assume b1 = 135 mm, b2= 50 mm, b3= 205 mm, d1= 65 mm, d2= 180 mm, dz= 65 mm. Determine the maximum horizontal shear stress in this segment of the beam.If M, = 285 kip-ft, find the magnitude of the bending stress at a point H For the beam cross section, assume a = 9 in. b= 12 in. d= 31 in r= 45 in. The centroid of the cross section is located 14.16 in. below the uppermost surface of the beam. The moment of inertia about the z axis is 26227 in 4a. Calculate the moment of inertia (I) of the given cross–section b. Calculate the first moment of area (Q) at certain depth by using 25 mm increments. c. Calculate and draw the horizontal shear stress distribution of the beam at 0.2 m from the left support