If the electronegativity of the elements is 1.8 and 4.0 eV, respectively, what is the ionic resonance energy between these two elements in kg / mol?

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter20: Chemistry Of Hydrogen, Elements In Group 3a Through 6a, And The Noble Gases
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Problem 20.3QE
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If the electronegativity of the elements is 1.8 and 4.0 eV, respectively, what is the ionic resonance energy between these two elements in kg / mol?

Expert Solution
Step 1

According to the pauling's scale

(XA - XB) = √Δ

where 

XA = electronegativity of element A

XB = electronegativity of element B

Δ = resonance energy in electronvolt(ev)

1ev/atom = 23.06Kcal/mol

to convert the value of ev into Kcal/mol we will divide the value by 23.06Kcal/mol

XA-XB = √Δ/23.06 Kcal/mol

so above formula will become 

XA - XB = 0.208√Δ

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