If the roots of the auxiliary equation of a second order linear homogeous ODE are k1 > 0 and -k2 < 0, then the solution is x(t) = Aekit + Be-k2t For most choice of initial conditions x(0) = x0, i(0) = Yo we will have that x(t) → ±∞ as t → o. However, there are some special initial conditions for which x(t) → 0 as t → 0. Find the relationship between xo and yo that ensures this.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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If the roots of the auxiliary equation of a second order linear homogeous ODE are
ki > 0 and -k2 < 0, then the solution is
x(t) = Aekit + Be-k2t
For most choice of initial conditions
x(0) = xo, i(0)
= Yo
we will have that x(t) → ±∞ as t → . However, there are some special initial
conditions for which x(t) → 0 as t → 0. Find the relationship between xo
and
Yo
that
ensures this.
Transcribed Image Text:If the roots of the auxiliary equation of a second order linear homogeous ODE are ki > 0 and -k2 < 0, then the solution is x(t) = Aekit + Be-k2t For most choice of initial conditions x(0) = xo, i(0) = Yo we will have that x(t) → ±∞ as t → . However, there are some special initial conditions for which x(t) → 0 as t → 0. Find the relationship between xo and Yo that ensures this.
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