If this code prints [5, 3, 10], what is not a possible value for the sum of all elements of the original array a? а. 18 b. 16 с. 27 d. trick question, all values are possible for a suitably chosen array a and function f
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- Write a function that gets an array of points and sorts the array using qsort(). Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)½ is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation: (1,1) is first because 12+12=2 is the smallest (3,2) is next because 32+22 = 13 is the second smallest Both (3,4) and (5,0) have the same sum of squares, 25, but 3<5 so…Write a program to overload the function call operator ( ) so as to allow the more common form of double-array subscripting. Therefore, instead of saying: chessBoard[row][column] for an array of objects, overload the function call operator to allow the alternate form: chessBoard(row, column) A sample output of your program should look like follows: The value of each array element is the product of the row and column values. Using the class definition given in the myClassOperator.h header file below, implement the class member functions and driver code in separate files.Implement the following function, without using any data structure. /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2)
- An array with any number of elements is said to be repeating if any two or more of the elements are appearing in sequential an indexes after each other.Write a C++ function that accepts an integer array and returns 1 or “Repeating” if it is a repeating array, otherwise it returns 0 or “Not Repeating”. For Instance:2, 3, 5, 6, 7, 7, 7, 6, 8, 10 - Repeating2, 3, 4, 6, 4, 6, 4, 7, 8, 9 - Not repeatingWrite the following three functions: a) The function gets an array A of length n of ints, and a boolean predicate pred. It returns the smallest index i such that pred(A[i])==true.If no such element is not found, the function returns -1.int find(int* A, int n, bool (*pred)(int)); b) The function gets an array A of length n of ints, and a function f. It applies f to each element of A.void map(int* A, int n, int (*f)(int)); c) The function gets an array A of length n of ints, and a function f. The function f gets 2 ints and works as follows: Start with accumulator = A[0] For i=1...length-1 compute accumulator=f(accumulator, A[i]) Return accumulator For example, if f computes the sum of the two inputs, then reduce() will compute the sum of the entire array.int reduce(int* A, int n, int (*f)(int,int));Implement a function GetMinimumCutSegments(int[] arr, int k) that takes in an array arr of positive integers and an integer k, and returns the minimum number of contiguous segments of the array that must be concatenated to form an array of size k. The function should return -1 if it is not possible to create an array of size k by concatenating contiguous segments of the input array. Example: Input: [1, 2, 3, 4], 6 Output: 2 Explanation: The minimum number of contiguous segments that must be concatenated to form an array of size 6 is 2. The two segments that can be concatenated are [1, 2] and [3, 4]. Input: [1, 2, 3, 4], 7 Output: -1 Explanation: It is not possible to create an array of size 7 by concatenating contiguous segments of the input array. Constraints: The input array arr will have at most length 100. The integer k will be at least 1 and at most 10^6. Can you write a C# function that solves this problem? public int GetMinimumCutSegments(int[] arr, int k) { // Your code…
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- You are given the array-like data structure Listy, which does not have a size.method. It does, however, provide an elementAt I function that returns the element at index I in the array of elements. 0( 1) time. If I exceeds the data structure's boundaries, it returns -1. (As a result, the data structure only works with positive numbers.) Given a Listy of sorted positive integer ,Determine the index at which an element x appears. If x happens more than once, you may return any index.Write a function is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4Write a function that takes two int arrays arr1 and arr2, and their size n as parameters. The functionreturns the number of elements that exist in arr1 and arr2 with indexes i1 and i2 respectively such that i1>=i2.(Example: arr1: [ 1,5,2,3,4,0,7] arr2: [0,1,3,7,4,2] then the function returns 3 ( 0,3,7) )