Refer to the photo. The first part has been solved The prevalence of cannabis use among Canadians 15 years of age and older was 9.1% in2011(according to Statistics Canada).уearsIf we were to sample n = 125 individuals, what would be the approximateThe mean is calculated as:distribution of the sample proportion îp ? give the mean, the standard deviation andthe name of the approximate distribution of such sample proportion as well as thename of the theorem used to justify your claimsH=n•p=125 - 0.091 = 11.375%3DThe variance is calculated as:o² = n·p· (1 – p) = 125 - 0.091 · 0.909 = 10.3399%3|The standard deviation is calculated as:= yn•p·(1 – p)= V10.3399 = 3.2156%3DIf we assume that the above proportion is still true in 2021, how likely is itto find a random sample of n =125 individuals that results in a sample proportionexceeding 11% ?

Obtain the probability that sample proportion is exceeding 0.11. The probability that sample…

Answered: If we assume that the above proportion…

If we assume that the above proportion is still true in 2021, how likely is it to find a random sample of n exceeding 11% ? 125 individuals that results in a sample proportion %3D

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Question

Refer to the photo. The first part has been solved

The prevalence of cannabis use among Canadians 15 years of age and older was 9.1% in
2011(according to Statistics Canada).
уears
If we were to sample n = 125 individuals, what would be the approximate
The mean is calculated as:
distribution of the sample proportion îp ? give the mean, the standard deviation and
the name of the approximate distribution of such sample proportion as well as the
name of the theorem used to justify your claims
H=n•p=125 - 0.091 = 11.375
%3D
The variance is calculated as:
o² = n·p· (1 – p) = 125 - 0.091 · 0.909 = 10.3399
%3|
The standard deviation is calculated as:
= yn•p·(1 – p)
= V10.3399 = 3.2156
%3D
If we assume that the above proportion is still true in 2021, how likely is it
to find a random sample of n =
125 individuals that results in a sample proportion
exceeding 11% ?

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