If yi = 1, Y2 = In a are two linearly indepen- dent solutions of ry"+y' = 0, then the partic- ular solution of xy"+y' = f(x) can be written as yp(x) = %3D

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
Problem 69EQ: Let x=x(t) be a twice-differentiable function and consider the second order differential equation...
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If y1 = 1, Y2 = In a
are two linearly indepen-
dent solutions of ry" +y' = 0, then the partic-
ular solution of xy" +y' = f(x) can be written
as yp(x) =
%3D
(A) fa In a f(x) da
– In a f af(æ) da
-
(B) – In a f f(x) da + faf(x) da
(C) - fa Ina f(x) da + In r Saf(x) da
(D) - f In r f(x) dr + In a f f (x) da
(E) None
Transcribed Image Text:If y1 = 1, Y2 = In a are two linearly indepen- dent solutions of ry" +y' = 0, then the partic- ular solution of xy" +y' = f(x) can be written as yp(x) = %3D (A) fa In a f(x) da – In a f af(æ) da - (B) – In a f f(x) da + faf(x) da (C) - fa Ina f(x) da + In r Saf(x) da (D) - f In r f(x) dr + In a f f (x) da (E) None
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