If you build and run the code shown below. The value of b is .. ........ #include #include int main() int b, c, d; b =7; c=++b; d=--c; b=d; printf ("The value of b is %i",b); return 0;

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Q: What is the value stored at x, given the statements? int x; x = 6/ static_cast (4.5 + 6.4);

A: The answer is..

Q: What is the value stored at x, given the statements? int x; x = 6/ static_cast (4.5 + 6.4);

A: The answer is

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