If you dissolve lead (II) nitrate and potassium iodide in water, they will react to form lead (II) iodide and potassium nitrate. Pb(NO3)2 + 2 KI PbI2 + 2 KNO3 A. Calculate the grams of lead (II) iodide that can be produced from 15.00 moles of potassium iodide. B. Calculate the grams of lead (II) iodide that can be produced from 44.00 grams of potassium iodide.
If you dissolve lead (II) nitrate and potassium iodide in water, they will react to form lead (II) iodide and potassium nitrate. Pb(NO3)2 + 2 KI PbI2 + 2 KNO3 A. Calculate the grams of lead (II) iodide that can be produced from 15.00 moles of potassium iodide. B. Calculate the grams of lead (II) iodide that can be produced from 44.00 grams of potassium iodide.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter3: Stoichiometry
Section: Chapter Questions
Problem 117E: Bacterial digestion is an economical method of sewage treatment. The reaction is an intermediate...
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1. If you dissolve lead (II) nitrate and potassium iodide in water, they will react to form
lead (II) iodide and potassium nitrate.
Pb(NO3)2 + 2 KI PbI2 + 2 KNO3
A. Calculate the grams of lead (II) iodide that can be produced from 15.00 moles of
potassium iodide.
B. Calculate the grams of lead (II) iodide that can be produced from 44.00 grams of
potassium iodide.
2. Two moles of propane reacts with 8 moles of oxygen gas in a combustion reaction.
What is the limiting reactant? Excess reactant? How many moles of CO2 are formed?
How much of the excess reactant is left over?
C3H8 + 5 O2 3 CO2 + 4 H2O
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