(a) Determine the area under a normal distribution curve with μ = 55 and o = 7 i. To the right of x = 58 ii. to the right of x = 43

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(a) Determine the area under a normal distribution curve with μ = 55 and o = 7
i. To the right of x = 58
ii. to the right of x = 43
(b) A random sample of sixteen (16) SDC workers taken from the management level of the company gives a
mean monthly salary of $17,000 with a standard deviation of $5500.
What is the 98% confidence interval for the population mean of management level employees?
(c) The HR manager at Swift Delivery Company (SDC) has been investigating the level of job satisfaction of
various employees at different levels of the organization. She categorized the jobs into levels of seniority 1
to 12, with 12 being the most senior and 1 being the least senior. The CEO and Board of Directors (levels 13
- 14) were not surveyed. Job satisfaction was rated as a score out of 80. Choosing one person at random
from each of the twelve levels she collected the following data:
Transcribed Image Text:(a) Determine the area under a normal distribution curve with μ = 55 and o = 7 i. To the right of x = 58 ii. to the right of x = 43 (b) A random sample of sixteen (16) SDC workers taken from the management level of the company gives a mean monthly salary of $17,000 with a standard deviation of $5500. What is the 98% confidence interval for the population mean of management level employees? (c) The HR manager at Swift Delivery Company (SDC) has been investigating the level of job satisfaction of various employees at different levels of the organization. She categorized the jobs into levels of seniority 1 to 12, with 12 being the most senior and 1 being the least senior. The CEO and Board of Directors (levels 13 - 14) were not surveyed. Job satisfaction was rated as a score out of 80. Choosing one person at random from each of the twelve levels she collected the following data:
Seniority Level
Σ* =78
ΣSS = 953
X
1
2
3
4
5
6
7
8
9
10
11
12
Job Satisfaction Rating
Σv= 630
y
52
63
67
61
58
50
52
44
46
40
38
Ex = 650
SS=-226 SS = 143
x 6.5
= 52.5
(i) Find the equation of the least squares regression line for the data.
(ii) Calculate the correlation coefficient, r, and interpret the result.
(iii) Calculate the coefficient of determination, ²,
(iv) What job satisfaction score would you expect to see for a person working at a seniority level of 10?
59
Σμ = 34028
;
Σαν = 3869
Transcribed Image Text:Seniority Level Σ* =78 ΣSS = 953 X 1 2 3 4 5 6 7 8 9 10 11 12 Job Satisfaction Rating Σv= 630 y 52 63 67 61 58 50 52 44 46 40 38 Ex = 650 SS=-226 SS = 143 x 6.5 = 52.5 (i) Find the equation of the least squares regression line for the data. (ii) Calculate the correlation coefficient, r, and interpret the result. (iii) Calculate the coefficient of determination, ², (iv) What job satisfaction score would you expect to see for a person working at a seniority level of 10? 59 Σμ = 34028 ; Σαν = 3869
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iii) and iv)

Σ* =78
ΣSS = 953
Seniority Level
X
1
2
3
4
5
6
7
8
9
10
11
12
Σv= 630
Ex = 650
SS₂ = -226 SS = 143
Job Satisfaction Rating
y
52
63
67
61
58
50
52
44
46
40
38
59
Σμ = 34028
;
Σαν = 3869
x 6.5 = 52.5
(iii) Calculate the coefficient of determination, ²,
(iv) What job satisfaction score would you expect to see for a person working at a seniority level of 10?
Transcribed Image Text:Σ* =78 ΣSS = 953 Seniority Level X 1 2 3 4 5 6 7 8 9 10 11 12 Σv= 630 Ex = 650 SS₂ = -226 SS = 143 Job Satisfaction Rating y 52 63 67 61 58 50 52 44 46 40 38 59 Σμ = 34028 ; Σαν = 3869 x 6.5 = 52.5 (iii) Calculate the coefficient of determination, ², (iv) What job satisfaction score would you expect to see for a person working at a seniority level of 10?
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