iii) The switch Si in Figure 5 is closed for long time and then opened at t= 0, calculate the voltage across the air gap between the switch contacts at f 0. Assume the resistance of the air gap is 1.2MQ. 1=0 2 kN 4 kfN 30 V 12 mH Figure 5

iii) The switch Si in Figure 5 is closed for long time and then opened at t= 0, calculate the voltage across the air gap between the switch contacts at f 0. Assume the resistance of the air gap is 1.2MQ. 1=0 2 kN 4 kfN 30 V 12 mH Figure 5

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter27: Service-entrance Equipment

Section: Chapter Questions

Problem 44R

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

iii) The switch S, in Figure 5 is closed for long time and then opened at t= 0, calculate the
voltage across the air gap between the switch contacts at t= 0. Assume the resistance of the
air gap is 1.2MQ.
4 kfN
=0 2 kn
30 V
12 mH
Figure 5

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