following for a thermistor R(ohm) T(C) 120.98+4 68.654 134.01+4 45.978 170.224+44*4 35.127 For a measured resistance of 44^2+1.23 ohms, to find the value of temperature in 0C by using Gauss Elimination method.

following for a thermistor R(ohm) T(C) 120.98+4 68.654 134.01+4 45.978 170.224+44*4 35.127 For a measured resistance of 44^2+1.23 ohms, to find the value of temperature in 0C by using Gauss Elimination method.

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter19: Special-purpose Outlets-water Pump, Water Heater

Section19.2: Water Heater Branch Circuit

Problem 8R: For residential water heaters, the Consumer Product Safety Commission suggests a maximum temperature...

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Concept explainers

Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

An accurate representation of a thermistor curve between Resistance (ohm) and Temperature (0C) is generally given by

1/T=ao+a1 (ln ( R) )+a2( ln ( R)2)
Where T is temperature in Kelvin, R is resistance in ohms, and ao,a1, a2 are constants of the curve. Given the following for a thermistor

R(ohm)	T(C)
120.98+4	68.654
134.01+4	45.978
170.224+44*4	35.127

For a measured resistance of 44^2+1.23 ohms, to find the value of temperature in 0C by using Gauss Elimination method.

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