implement getbyte function. getByte(x,n) Extract byte n from word x /* * getByte - Extract byte n from word x * Bytes numbered from 0 (LSB) to 3 (MSB) * Examples: getByte(0x12345678,1) = 0x56 * Legal ops: ! ~ & ^ | + << >> * Max ops: 6 */ int getByte(int x, int n) { return 2; }
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implement getbyte function.
getByte(x,n) Extract byte n from word x
* getByte - Extract byte n from word x
* Bytes numbered from 0 (LSB) to 3 (MSB)
* Examples: getByte(0x12345678,1) = 0x56
* Legal ops: ! ~ & ^ | + << >>
* Max ops: 6
*/
int getByte(int x, int n) {
return 2;
}
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- implement byteSwap(x,n,m) Swap the m and n byte of x /* * byteSwap - swaps the nth byte and the mth byte* Examples: byteSwap(0x12345678, 1, 3) = 0x56341278* byteSwap(0xDEADBEEF, 0, 2) = 0xDEEFBEAD* You may assume that 0 <= n <= 3, 0 <= m <= 3* Legal ops: ! ~ & ^ | + << >>* Max ops: 25*/ int byteSwap(int x, int n, int m) {return 2;}Computer Science you are given a string X of length n and another string Y of length m ≤n. Say,the indexes p1, p2, p3, p4 and q1, q2, q3, q4 form two sub-sequences, i.e., 0 ≤ p1 < p2 < p3 < p4 < nand 0 ≤q1 < q2 < q3 < q4 < n; then, they are non-overlapping if p4 < q1.The task is to count the maximum number of non-overlapping sub-sequences of X that are thesame as Y . Thus, if X = GAXTYAWBGTAUGBTABGRGTAXB and Y = GTAB, then the answer is3 as shown by the red fonts. We cannot select the underlined GTAB as it overlaps with a red GTAB(i.e., among overlapping sub-sequences, you can select only one of them).Describe an O(m + n) time algorithm to obtain the count. Write a pseudo-code.A set of integers 0..MAX may be implemented using an array of boolean values. This particular implementation is called a bit-vector implementation of a Set. Since C doesn’t have the Boolean data type, then substitute TRUE with 1 and FALSE with 0, or define 1 and 0 as TRUE and FALSE, respectively.For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE. For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE.For example: if s = {3,4,6,8}, the array looks like this: Implement a programmer-defined data type called BitSet to represent a set as follows:typedef int BitSet[MAX];Implement the following functions:void initialize(BitSet s); - set all array elements to FALSEvoid add(int elem,BitSet s);- set the item indexed by elem to…
- Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)Implement the following function, without using any data structure or #include <bits/stdc++.h> /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2) THIS IS NOT THE CORRECT SOLUTION / include headers #include <bits/stdc++.h> // deinfe the namespace using namespace std; // function fo rchecking same bool…Consider the following problem on a dictionary of n words, W1...Wn, each with exactly k characters. You can transform a word Wi into word Wj if they differ in at most d≤k characters. (both dd and kk are specified as part of the input, along with n and the words) For example, if the dictionary is: W1 = 'hit', W2 = 'cog', W3 = 'hot', W4 = 'dot', W5 = 'dog', W6 = 'lot', W7 = 'log', and d=1d=1, one way to change 'hit' to 'cog' is: 'hit' →→ 'hot' →→ 'dot' →→ 'dog' →→ 'cog'. We want to find the fewest number of steps to transform W1 to W2. Q1.1 I claim that this problem be formulated as a shortest path problem. Please provide a strategy to formulate this as the shortest path problem and give a graph visualization of the problem Q1.2 Show that your graph (in Q 1.1) can be constructed in O(n^2) time, and its size is up to O(n^2).
- Implement a class RLE that uses fixed-length encoding, to compress ASCII bytestreams using relatively few different characters, includingthe code as part of the encoded bitstream. Add code to compress() to make a stringalpha with all the distinct characters in the message and use it to make an Alphabet foruse in compress(), prepend alpha (8-bit encoding plus its length) to the compressedbitstream, then add code to expand() to read the alphabet before expansion.JAVA:Use the "natural split" algorithm on the file split.txt and answer the following question: How many elements are in the first list? (Split into two files.) Splt.txt 200494 774 644 345 521 61 27 28 584 569 66 857 210 2 211 675 548 596 188 647 671 517 408 475 615 113 731 522 850 17 640 940 556 517 602 935 76 578 880 428 168 394 381 497 247 368 137 138 619 973 895 106 838 45 921 800 681 660 490 427 937 917 786 959 152 604 837 749 684 963 926 963 988 492 385 458 788 7 62 46 932 996 787 634 34 616 71 128 686 578 923 532 933 545 100 224 895 595 342 933 934 797 120 565 495 884 237 648 843 599 157 843 192 279 301 649 382 881 667 178 126 746 44 601 22 52 769 708 991 83 447 786 525 168 328 922 153 367 22 689 834 774 93 110 547 597 644 726 237 20 370 573 391 225 750 897 956 839 951 455 8 509 746 338 576 276 277 341 274 891 723 53 966 271 50 990 493 823 833 306 619 461 768 832 736 759 920 451 549 833 911 123 907 225 252 179 177 272 747 859Write a program that implements a sorted list using dynamic allocated arrays. DataFile.txt contains the information of poker cards. C: clubs(lowest),D: diamonds, H: hearts, S:spades(highest) 2 (lowest), 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A No Joker cards Any C cards are lower than any D cards. DataFile Content(You can write the file specification into your program.): H4,C8,HJ,C9,D10,D5,DK,D2,S7,DJ,H3,H6,S10,HK,DQ,C2,CJ,C4,CQ,D8,C3,SA,S2,HQ,S8,C6,D9,S3,SQ ,C5,S4,H5,SJ,D3,H8,CK,S6,D7,S9,H2,CA,C7,H7,DA,D4,H9,D6,HA,H10,S5,C10 H4, D5, HK, D2 H4, HK, SK C9,C10 For examples, DJ means J of Diamonds;H7 means 7 of hearts. Your job Create a list by dynamic allocated array and set the size to 20 Read the first 20 cards in the first line of the file, the put them one by one into the list by implementing and using putItem(). The list must be kept sorted in ascending order. Then print out all the cards in the list in one line separating by commas. Then delete the cards indicated in the second…
- Write a c++ code that implement a loop that accesses a number of different locations in an array over-and-over again, and see how the average access time changes as the array size increases, from a size small enough to fit in L1 cache to a size too large to fit in L2 (or L3) cache. Try to estimate the sizes of your caches.Implement function rotate that takes a string argument s and an integer argument n, and rotates the string s to the left by n times. For example, the code char s[] = "systems"; rotate(s, 3); will change s into "temssys", while the code char t[] = "abcd"; rotate(t, 1); will change t into "bcda". void rotate(char *w, int j)JAVA: Use the "natural split" algorithm on the file split.txt and answer the following question: How many elements are in the first list? Split.txt file 200494 774 644 345 521 61 27 28 584 569 66 857 210 2 211 675 548 596 188 647 671 517 408 475 615 113 731 522 850 17 640 940 556 517 602 935 76 578 880 428 168 394 381 497 247 368 137 138 619 973 895 106 838 45 921 800 681 660 490 427 937 917 786 959 152 604 837 749 684 963 926 963 988 492 385 458 788 7 62 46 932 996 787 634 34 616 71 128 686 578 923 532 933 545 100 224 895 595 342 933 934 797 120 565 495 884 237 648 843 599 157 843 192 279 301 649 382 881 667 178 126 746 44 601 22 52 769 708 991 83 447 786 525 168 328 922 153 367 22 689 834 774 93 110 547 597 644 726 237 20 370 573 391 225 750 897 956 839 951 455 8 509 746 338 576 276 277 341 274 891 723 53 966 271 50 990 493 823 833 306 619 461 768 832 736 759 920 451 549 833 911 123 907 225 252 179 177 272 747 859