Python Language Make a happy number function IMPORTANT: Your isHappy function must not call itself.Subtask III: There are in fact many levels of happiness. The larger the number, the happier we feelabout that number. The k-th happy number is the k-th smallest happy number. This means, the 1sthappy number is the smallest happy number, which is 1. The 2nd happy number is the second smallesthappy number, which is 7. Below is a list of the first few happy numbers:1,7, 10, 13, 19, 23, 28, 31, 32, 44, 49, 68, 70, 79, 82, 86, 91, 94, 97, 100, 103, 109, 129, 130, 133,139, 167, 176, 188, 190, ...Implement a function kThHappy (k: int) -> int that computes and returns the k-th happy num-ber. For example:kThHappy (1) returns 1kThHappy (3) returns 10• kThHappy (11) returns 49• kThHappy (19) returns 97 Happy numbers are a nice mathematical concept. Just as only certain numbers are prime, only cer-tain numbers are happy-under the mathematical definition of happiness. We'll tell you exactly whathappiness means.The concept of happy numbers is only defined for whole numbers n> 1. To test whether a number ishappy, we can follow a simple step-by-step procedure:(1) Write that number down(2) Stop if that number is either 1 or 4.(3) Cross out the number you have now. Write down instead the sum of the squares of its digits.(4) Repeat Step (2)When you stop, if the number you have is 1, the initial number is happy. If the number you have is 4,the initial number is sad. There are only two possible outcomes, happy or sad.By this definition, 19 is a happy number because 12 + 92 = 82, then 82 + 22 = 68, then 62 + 8² = 100, andthen 12 + 02 + 0² = 1. However, 145 is sad because 12 + 42 +52 = 42, 42 +22 = 20, and 22 +02 = 4.Subtask I: First, you'll implement a function sumOfDigitsSquared(n: int) -> int that takes apositive number n and returns the sum the squares of its digits. For example,• sumOfDigitsSquared(7) should return 49sumOfDigitsSquared(145) should return 42 (i.e., 1**2 + 4**2 + 5**2 = 1 + 16 + 25)• sumOfDigitsSquared(199) should return 163 (i.e., 1**2 + 9**2 + 9**2 = 1 + 81 + 81)Subtask II: Then, you'll write a function isHappy (n: int) -> bool that takes as input a positivenumber n and tests if n is happy. You may wish to use what you wrote in the previous subtask.isHappy (100) should return True• isHappy (111) should return False• isHappy (1234) should return FalseisHappy (989) should return True(Did we tell you n must be positive (i.e. at least 1)?)

Algorithm: Start Implement SumOfDigitsSquared() method which returns sum of squares of each digit…

Answered: IMPORTANT: Your isHappy function must…

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter10: Classes And Data Abstraction

Section: Chapter Questions

Problem 19PE

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In python, Problem Description:Sheldon and Leonard are physicists who are fixated on the BIG BANG theory. In order to exchange secret insights they have devised a code that encodes UPPERCASE words by shifting their letters forward. Shifting a letter by S positions means to go forward S letters in the alphabet. For example, shifting B by S = 3 positions gives E. However, sometimes this makes us go past Z, the last letter of the alphabet. Whenever this happens we wrap around, treating A as the letter that follows Z. For example, shifting Z by S = 2 positions gives B. Sheldon and Leonard’s code depends on a parameter K and also varies depending on the position of each letter in the word. For the letter at position P, they use the shift value of S = 3P + K. For example, here is how ZOOM is encoded when K = 3. The first letter Z has a shift valueof S = 3 × 1 + 3 = 6; it wraps around and becomes the letter F. The second letter, O, hasS = 3 × 2 + 3 = 9 and becomes X. The last two letters…
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A proposition Q follows from a proposition P, if Q is never false when P is true. Suppose we want to check this in a particular case. Which of the following is correct? Select one: a. We need to check that whenever P is false, Q is also false. b. We need to check that whenever Q is false, P is also false. c. We need to check that whenever Q is true, P is also true. d. We need to check that Q is true when P is true, and that Q is false when P is false.
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Please help me Josephus Problem is a theoretical problem related to a certain counting-out game. On thiscase, people are standing in a circle waiting to be executed. After a specified number ofpeople are skipped, the next person is executed. The procedure is repeated with theremaining people, starting with the next person, going in the same direction and skippingthe same number of people, until one person remains, and is freed.Arrange the numbers 1 , 2, 3 , ... consecutively (say, clockwise) in a circle. Now removenumber 2 and proceed clockwise by removing every other number, among those thatremain, until one number is left. (a) Let denote the final number which remains. Find formula for .(b) If there are 70 people, what is the safe number (the number that remains)?
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Can someone help me to answer this activity? Factorial of a number is defined as: n! = n(n-1)(n-2)(n-3)...(2)(1) For example, 4! = 4*3*2*1 The n! can be written in terms of (n-1)! as: n! = n* (n-1)! (n-1)! = (n-1)*(n-2)! and so forth. Thus, in order to compute n!, we need (n-1)!, to have (n-1)!, we need (n-2)! and so forth. As you may immediately notice, the base case for factorial is 1 because 1! = 1. Write a program that uses a recursive function called factorial that takes an integer n as its argument and returns n! to the main.
Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…
Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…
use JAVA to write the code. : Euclid’s algorithm for finding the greatest common divisor (gdc) of two numbers The algorithm: given two numbers, n1 and n2: Divide n1 by n2 and let r be the remainder. If the remainder r is 0, the algorithm is finished and the answer is n2. (If the remainder is 1, the numbers are mutually prime and we are done-see below.) Set n1 to the value of n2, set n2 to the value of r, and go back to step 1. Entering 0 for one of the values is bad. It should work for the other value, but you have to figure out which is OK and which is bad. Catch this problem as it happens and make the user enter another value until they enter an acceptable one. Give an appropriate error message if this happens.

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