In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below What is the value of the degree of freedom for this test? What is the p-value for this test? Carefully define the null and alternative hypotheses of the χ2 test underlying the generation of the above table. Using α = 10%, what is the conclusion of this test? Give reasons for your
In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below What is the value of the degree of freedom for this test? What is the p-value for this test? Carefully define the null and alternative hypotheses of the χ2 test underlying the generation of the above table. Using α = 10%, what is the conclusion of this test? Give reasons for your
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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3) In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below
- What is the value of the degree of freedom for this test?
- What is the p-value for this test?
- Carefully define the null and alternative hypotheses of the χ2 test underlying the generation of the above table.
- Using α = 10%, what is the conclusion of this test? Give reasons for your answer.
Transcribed Image Text:In a business, the Chief Executive Officer wants to know if his workers are for or against
mandatory vaccinations. A random sample of 200 workers was taken and the results are shown
in the MINITAB output below
Expected counts are printed below observed counts
Managers
Team leaders
Employees
Total
17
22
15
Approve
21.330
17.820
14.850
54
34
25
14
Against
28.835
24.090
20.075
73
28
19
26
No Opinion
28.835
20.075
73
24.090
Total
79
66
55
200
Chi-sq
0.878992 +
0.980494 +
0.001515 +
=
0.925168+
0.034375 +
1.838387 +
0.02418 +
1.075471 +
1.74874
=7.507306
What is the value of the degree of freedom for this test?
ii.
i.
What is the p-value for this test?
Carefully define the null and alternative hypotheses of the x' test underlying the
generation of the above table.
iv.
111.
Using a = 10%, what is the conclusion of this test? Give reasons for your answer.
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