In a certain medical application, water at room temperature and pressure flows through a rectangular channel of length L = 22 cm, widths= 2.6 cm, and gap thickness b = 0.3 mm as shown in the diagram below. The volume flow rate is sinusoidal Q sin (21ft ). Assume that v =1 x 10 m2/s and p = with amplitude Q = 0.50 mL/s and frequency f = 20 Hz, i.e., Q = 0.001 Pa-s.

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Chapter6: Forced Convection Over Exterior Surfaces
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In a certain medical application, water at room temperature and pressure flows through a rectangular channel of length L =
22 cm, width s = 2.6 cm, and gap thickness b = 0.3 mm as shown in the diagram below. The volume flow rate is sinusoidal
with amplitude Q = 0.50 mL/s and frequency f = 20 Hz, i.e., Q = Q sin (2Tft ). Assume that v = 1 x 10 6 m2/s and u =
0,001 Pa-s.
b.
Calculate the maximum Reynolds number (Re = Vb / u) based on maximum average velocity and gap thickness. Channel flow like this
remains laminar for Re less than about 2000. If Re is greater than about 2000, the flow will be turbulent.
The Reynolds number is
17
of 17
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16
Transcribed Image Text:Required information In a certain medical application, water at room temperature and pressure flows through a rectangular channel of length L = 22 cm, width s = 2.6 cm, and gap thickness b = 0.3 mm as shown in the diagram below. The volume flow rate is sinusoidal with amplitude Q = 0.50 mL/s and frequency f = 20 Hz, i.e., Q = Q sin (2Tft ). Assume that v = 1 x 10 6 m2/s and u = 0,001 Pa-s. b. Calculate the maximum Reynolds number (Re = Vb / u) based on maximum average velocity and gap thickness. Channel flow like this remains laminar for Re less than about 2000. If Re is greater than about 2000, the flow will be turbulent. The Reynolds number is 17 of 17 Next > Prev 16
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