In a nuclear reactor accident, the 137Cs (?1/2 = 30.2 years) nuclide is among the most problematic fission products. The energy released by the B-decay of 137Cs into the stable 137Ba is 1.17 MeV. a) Why is 137Cs considered as one of the most problematic fission products in a reactor accident? Give two reasons.

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Chapter29: Nuclear Physics
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In a nuclear reactor accident, the 137Cs (?1/2 = 30.2 years) nuclide is among the most problematic fission products. The energy released by the B-decay of 137Cs into the stable 137Ba is 1.17 MeV.

a) Why is 137Cs considered as one of the most problematic fission products in a reactor accident? Give two reasons.

b)Give two possible ways that 137Cs is produced in a pressurized water reactor. Write down the corresponding equation in each process.

c)What is the percentage of a sample of 137Cs that will decay in one year? [Hint: the lifetime r is related to the half-life ?1/2 by r = ?1/2 ln2 .]

d)If the radiation dose limit is 20 mSv per annum, what is the maximum amount of 137Cs that a 60-kg person can swallow without affecting his health?

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