# In a period of 1.0 s, 5.0 x 1023 nitrogen molecules strike a wall of area 8.0 cm2. If the molecules move at 3.00 x 102 m/s and strike the wall head-on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68 x 10-26 kg.)

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In a period of 1.0 s, 5.0 x 1023 nitrogen molecules strike a wall of area 8.0 cm2. If the molecules move at 3.00 x 102 m/s and strike the wall head-on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68 x 10-26 kg.)

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Step 1

Given, help_outlineImage TranscriptioncloseNumber of molecules,n=5×10²³ Area,A =8 cm² =8×10 m² Velocity,v = 300 m/s Mass of N,, m = 4.68 × 106 Kg fullscreen
Step 2

Since the collision of molecule is perfectly elastic collision so velocity will be remain same even after collision but direction will change. Force can be calculated using Newton’s Second law, help_outlineImage TranscriptioncloseAv F = n m- At where,n=Number of molecules m = Mass of body Av =v, –V; v, = -300 m/s(-ve sign for initially taking direction as negative) v, = 300 m/s (Sign will be opposite to initial) Av = 300 – (-300) %3D Av = 600 m/s fullscreen
Step 3

By plugging in the given values to...

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