Question
Asked Dec 24, 2019
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In a period of 1.0 s, 5.0 x 1023 nitrogen molecules strike a wall of area 8.0 cm2. If the molecules move at 3.00 x 102 m/s and strike the wall head-on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68 x 10-26 kg.)

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Expert Answer

Step 1

Given,

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Number of molecules,n=5×10²³ Area,A =8 cm² =8×10 m² Velocity,v = 300 m/s Mass of N,, m = 4.68 × 106 Kg

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Step 2

Since the collision of molecule is perfectly elastic collision so velocity will be remain same even after collision but direction will change. Force can be calculated using Newton’s Second law,

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Av F = n m- At where,n=Number of molecules m = Mass of body Av =v, –V; v, = -300 m/s(-ve sign for initially taking direction as negative) v, = 300 m/s (Sign will be opposite to initial) Av = 300 – (-300) %3D Av = 600 m/s

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Step 3

By plugging in the given values to...

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Av F = n m- At -(3-10*|(46. 600 F = (5×10²3) ( 4.68× 10¯ F =14.04 N

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