In a random sample of 625 adults, 225 of them are smoke. The 95% confidence interval for the true value of adults who are smoke is O none

Q: In a recent poll, 360 people were asked if they liked dogs, and 92% said they did. Find the margin…

A:

Q: If n = 340 and p^=0.92, find the margin of error at a 90% confidence level E= Give your answer to…

A: Given,n=340p^=0.921-p^=1-0.92=0.08α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: Find the value of ta for a 99% confidence interval when sample size is 30

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer one question at a…

Q: In a recent poll, 360 people were asked if they liked dogs, and 74% said they did. Find the margin…

A: Critical value: The value of α is 0.10 for 90% confidence level. Using excel formula…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a recent poll, 280 people were asked if they liked dogs, and 51% said they did. Find the margin…

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Q: In a recent poll, 500 people were asked if they liked dogs, and 92% said they did. Find the margin…

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Q: In a recent poll, 300 people were asked if they liked dogs, and 89% said they did. Find the margin…

A: Solution: From the given information, p-hat=0.89 and n=300.

Q: In a recent poll, 550 people were asked if they liked dogs, and 10% said they did. Find the margin…

A: Givensample size(n)=550p^=10%=0.10confidence level=99%

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: In a recent poll, 530 people were asked if they liked dogs, and 81% said they did. Find the margin…

A: It is given that the value of n is 530, p hat is 0.81 and the confidence level is 0.99. Now,…

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

A: Given data: The given upper limit is b=20.75. The given lower limit is a=13.05.   The expression for…

Q: Find the 95% confidence interval for the mean score of all such subjects. Round to one decimal…

A: Given : n=27 , X-bar=76.2  , s=21.4  , α=0.05 Since , the population standard deviation (σ) is…

Q: In a recent poll, 120 people were asked if they liked dogs, and 29% said they did. Find the margin…

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Q: A pew Poll conducted in 2013 surveyed a random sample of 2003 adult Americans, and 18% of them said…

A: The random variable X follows normal distribution. We have to construct 90% confidence interval.…

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: In a random sample, 136 of 400 people given a flu vaccine experienced some discomfort. Construct a…

A: Given information n = 400 People No of people given vaccine x = 136

Q: In a recent poll, 500 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: Here we need to find the Margin of error corresponding to 95% confidence level.

Q: In a recent poll, 150 people were asked if they liked dogs, and 88% said they did. Find the margin…

A: Given Sample size=n=150 Sample proportion=p^=0.88 Confidence interval=99%

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

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Q: consider  a random sample of 300 students in a university,75 of them declared that they like playing…

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Q: In a recent polI, 200 people were asked if they liked dogs, and 15% said they did. Find the margin…

A: From the provided information, Sample size (n) = 200 15% people said they like dogs that is p̂ =…

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: In a recent poll, 560 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Margin of error (E): The margin of error for proportion p is given by,

Q: n a recent poll, 500 people were asked if they liked dogs, and 92% said they did. Find the margin of…

A: Given data, n=500 p=92%=0.92 Z value at 90% confidence is Zc=1.645 margin of error(E)=?

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: In a recent poll, 289 people were asked if they liked dogs, and 17% said they did. Find the margin…

A: Let X be the number of people who liked dogs Given: Number of people or sample size (n) = 289…

Q: In a recent poll, 260 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: In a random sample of 145 students, we find that 53% have attended a baseball game at some point in…

A: Given,sample size (n)=145sample proportion(p^)=0.53α=1-0.95=0.05α2 =0.025z0.025 =1.96

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: In a recent poll, 170 people were asked if they liked dogs, and 24% said they did. Find the margin…

A:

Q: If n=110 and ˆpp^ (p-hat) =0.71, find the margin of error at a 90% confidence level Give your…

A: Sample size n = 110 Sample proportion p^ = 0.71 Confidence level = 90% Formula Used: Margin of error…

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: A survey of 503 women shoppers found that 46% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 503 confidence level,c=0.99

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: In a recent poll, 120 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: In a poll, 120 people were asked if they liked dogs, and 67% said they did. So, n=120p=0.67

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

A:

Q: find tc for a 95% confidence level when the sample size is 6.

A: level of significance, alpha = 0.05from standard normal table, two tailed t alpha/2 with n-1 = 6 d.f…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: In a certain state, a survey of 500 workers showed that 38% belonged to a union.  Find the 93%…

A: Computation of critical value: 1-α=0.93α=0.07α2=0.0351-α2=0.965 The critical value of z-distribution…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: In a recent poll, 500 people were asked if they liked dogs, and 94% said they did. Find the margin…

A:

Q: In a recent poll, 100 people were asked if they liked dogs, and 90% said they did. Find the margin…

A: Obtain the margin of error at the 95% confidence level. The margin of error is obtained below as…

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: In a recent poll, 240 people were asked if they liked dogs, and 47% said they did. Find the margin…

A: Obtain the margin of error at the 90% confidence level. The margin of error at the 90% confidence…

Q: In a recent poll, 210 people were asked if they liked dogs, and 59% said they did. Find the margin…

A: Find z-critical value:…