consider  a random sample of 300 students in a university,75 of them declared that they like playing football. construct a 99% confidence interval fort the proportion of all students who would like to play football.

Q: 12. In a sample of 600 Canadians, 265 say they would rather retire in the US than in Canada.…

A:

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: In this question, It has been given that Margin of error = 0.05 and level of significance = 0.005.…

Q: In a random sample of 145 UNO students, we find that 53% have attended a Maverick hockey game at…

A:

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: When a survey asked subjects whether they would be willing to accept cuts in their standard of…

A: It is given that 362 out of 1,180 subjects respond yes.The sample proportion is 362/1,180 =…

Q: From a survey of 400 new Wawasan Open University students chosen at random, it was discovered that…

A:

Q: Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a 95%…

A: According to the given information, we have Total number of adults = 118 34 were found to have high…

Q: In a sample of 100,40 said they preferred Pepsi to Coke. A 95% confidence interval for the…

A:

Q: A Gallup poll of 1001 Americans age 18 and over conducted in May of 2013 found that 80% of the…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: For a single sample of n = 16 scores, the tabled t values used to determine the 99 percent…

A: Given: n = 16 Confidence Interval = 99% α=1-0.99=0.01α2=0.012=0.005 Degrees of freedom:…

Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

A:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: In a sample of 100, 40 said they preferred Pepsi to coke. A 95% confidence interval for the…

A:

Q: The Graduate Schools take a random sample of recent MS graduates (n=135) and finds that 12 of these…

A: Givenn=135x=12confidence interval = 90%p^=xn=12135=0.0889α=1-0.90=0.10α2=0.05zc=zα2=z0.05=1.6449…

Q: In a survey with human resources managers, 71% of respondents thought they should hire new staff…

A: Given information: Denote the population proportion of all respondents who thought that they should…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: A researcher asks 600 people if they received a flu vaccine, and 65% said they did. What is the 95%…

A: From the provided information Sample size (n) = 600 65% said they received a flu vaccine that is…

Q: n a recent poll, 500 people were asked if they liked dogs, and 92% said they did. Find the margin of…

A: Given data, n=500 p=92%=0.92 Z value at 90% confidence is Zc=1.645 margin of error(E)=?

Q: Identify the y-score for a 99% confidence interval if the sample size is 35.

A: We have to find critical value for given data..

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: If n=200 and ˆpp^ (p-hat) =0.39, find the margin of error at a 99% confidence level

A: Find z-critical value:…

Q: An investigator computes a 95% confidence interval for a population mean on the basis of a sample of…

A: To find half of width, We need to calculate 4 times the sample Size.

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: The formula for the sample size is as follows:

Q: If n=110 and ˆpp^ (p-hat) =0.71, find the margin of error at a 90% confidence level Give your…

A: Sample size n = 110 Sample proportion p^ = 0.71 Confidence level = 90% Formula Used: Margin of error…

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: 3. In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: Given : Sample size of people (n) = 300 Let X : No. of people from sample  who said they watched…

Q: A survey of 503 women shoppers found that 46% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 503 confidence level,c=0.99

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95%…

A: Obtain the 95% confidence interval for the true proportion of students ready for summer break. The…

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

A:

Q: in a recent survey of 1000 adults ages 18 to 40, 34% said they had no credit cards. find the 95%…

A: The sample size n=1000. The sample proportion is 0.34. The confidence level is 95%. The area between…

Q: Suppose you are designing a survey of firework plans among Kansas residents. You would like for the…

A: Here we need to find the required sample size with a 95% confidence level to estimate the number of…

Q: Identify the at-score for a 99% confidence interval if the sample size is 70.

A: givensample size(n)=70α=1-0.99=0.01

Q: 12. In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada.…

A: From the given information, Consider, X be the random variable that denotes the number of people who…

Q: In a certain state, a survey of 500 workers showed that 38% belonged to a union.  Find the 93%…

A: Computation of critical value: 1-α=0.93α=0.07α2=0.0351-α2=0.965 The critical value of z-distribution…

Q: consider a random sample of 300 students in a university, 75 of them declared that they like playing…

A: A random sample of 300 students in a university in which 75 of them declared that they like playing…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: The formula for the sample size is as follows:

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: In a sample of 500 Canadians, 225 say they would rather retire in Florida than in Canada. Calculate…

A:

Q: When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a…

A: The provided information is: It is given that 106 college students (s) own a car among 258 college…

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.