In a random sample of five people, the mean driving distance to work was 25.8 miles and the standard deviation was 4.4 miles Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean p. Interpret the results. Identify the margin of error. Hed

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 90%…

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Q: A metropolitan transportation authority has set a bus mechanical reliability goal of 3,900 bus…

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Q: 1. In a sample of 50 wine tasting rooms, the average amount of daily sale population standard…

A: As the population standard deviation is known, we will use z distribution.   (a) At 95% confidence…

Q: Use the given confidence interval to find the population proportion margin of error. 0.54 < p < 0.68

A: Confidence interval is given by 0.54 &lt; p &lt; 0.68 Now, the margin of error is given by,  MOE =…

Q: Listed below are speeds​ (mi/h) measured from traffic on a busy highway. This simple random sample…

A:

Q: The mean commuting distance of a random sample of 32 American adults was 9.50 miles, with a standard…

A: Given,sample size(n)=32sample mean(x)=9.50standard deviation(s)=6.92degrees of…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

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Q: The amount of material used in making a custom sail for a sailboat is normally distributed with a…

A: Given,Standard deviation σ = 64Sample size n = 15Sample mean x¯ = 912

Q: A nutritionist conducted a survey to study the body weight (kg) of 12 randomly selected patients…

A: Solution-: We have following data: 36,41,45,46,47,49,53,54,54,55,60,63 We want to find  (a) sample…

Q: find the t/α2 value for an 85% confidence interval for the mean when the sample size is 12

A: We have to find correct answer..

Q: Determine the sample size needed to construct a 95% confidence interval for the population mean, μ,…

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Q: The monthly earnings of a group of business students are normally distributed with a standard…

A: Given that  Margin of error =E =132 Population standard deviation =532 93% confidence level.

Q: Find the 90 percent confidence interval for the variance and standard deviation for the time it…

A: Solution :  Given : n = 27             s = 8.9 minutes             α = 0.1 Confidence interval for…

Q: A college admissions officer takes a simple random sample of 110 entering freshmen and computes…

A: Given,sample size(n)=110sample mean(x¯)=465population standard…

Q: listed below are speeds (mi/hr) measured from traffic on a busy highway. This simple random sample…

A:

Q: The average sa!lary of 64 employee was 5400 and the sample standard deviation was 260. Find the 95%…

A: Solution

Q: If the population standard deviation is sigma= 10, how large  a sample is necessary to have a…

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Q: Use the given confidence interval to find the margin of error and the sample mean.

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Q: The monthly earnings of a group of business students are normally distributed with a standard…

A: Given Standard deviations=532 Margin of error=132 At 93% confidence level the z is 1.81

Q: Given a mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95 %…

A: A mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95% confidence…

Q: Use a 0.05 level of significance to test the claim that the mean cost of a taxicab ride in New York…

A: The provided information is  x¯=12.04s=8.36n=40α=0.05a.The null and alternative hypothesis is…

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 270. Find the 90%…

A:

Q: For a group of 15 men subjected to a stressful situation, the mean number of heartbeats per minute…

A: Sample size (n) = 15Sample mean (x̅) = 126Standard deviations (s) = 4 Significance level (α) = 1-…

Q: (a) What sample size is required to obtain a 95% confidence interval with an approximate margin of…

A: It is given that margin of error (E) is 0.027 and the confidence level is 0.95.

Q: Estimate the mean of the population by constructing a 95% confidence interval

A: Given that Sample size n = 25 Sample mean = 150 Population SD = 12 The critical value of Z at 95%…

Q: A company wants to estimate the mean time (in hours) per week for an adult who uses computers at…

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Q: A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample…

A: Followings are the Explanation of the question  Use the t distribution to calculate t critical value…

Q: Given a mean of 62, a standard deviation of 8, and a sample size of 150, construct a 99.7%…

A: Given that a mean of 62, a standard deviation of 8 and a sample size of 150. We have to construct a…

Q: The ICU Admission dataset includes a variable indicating the age of the patient. Find and interpret…

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Q: A random sample of the number of farms (in thousands) in various states follows. Use these data to…

A: It is given that the population standard deviation is 31.

Q: For a sample of 35 items from a population for which the standard deviation is σ = 20.5, the sample…

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Q: An electrical firm manufactures light bulbs for LCD projectors. A randomly selected sample of 24…

A: We have given that,  Sample mean (x̄) = 600 hours, standard deviation (s) = 50 hours , sample size…

Q: Listed below are speeds​ (mi/h) measured from traffic on a busy highway. This simple random sample…

A: Number of samples (n) = 12 63 3969 64 4096 64 4096 56 3136 64 4096 53 2809 61…

Q: Given that the population standard deviation is 1, determine the minimum sample size needed in order…

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Q: For a given sample, a 50% confidence terval for the population mean is narrower than a 90%…

A: For  a given sample size and population standard deviation, the interval estimation of the…

Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

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Q: It is a simple random sample and it is normal. In the course of designing theater seats, the…

A: The sample mean is obtained below: Thus, the sample mean is 844.375.   The sample standard…

Q: Listed below are speeds (mi/h) measured from traffic on a busy highway. This simple random sample…

A:

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 260. Find the 90 %…

A:

Q: The amount of material used in making a custom sail for a sailboat is normally distributed with a…

A: Given σ=64, n=15  and  x¯=912

Q: Which distribution would be used to find the multiplier for this confidence interval? Select one: a.…

A: Given,n1=250X1=157n2=400X2=232

Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

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Q: Use The t Distribution Table to find the t2 value for a 98% confidence interval for the mean when…

A: Obtain the degrees of freedom.   The degrees of freedom is obtained below as follows:   From the…

Q: (b) A sample of size 15 drawn from a normally distributed population has sample mean 35 and sample…

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Q: The cell phone conversations of a random sample of 50 students has a standard deviation of 9.7…

A: Given: n=50σ=9.7CI=90%=0.90

Q: In a random sample of 50 people, the mean body mass index (BMI) was 27.7 and the standard deviation…

A: Given that the sample size is 50, the mean is 27.7 and the standard deviation is 6.12 a) Confidence…

Q: he following stemplot shows the swimming speeds, in kilometers per hour  (km/h), for a random sample…

A: xbar = 9.771 s = 0.944 n = 31

Q: A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample…

A: It is given that  Sample mean = $165.40 Sample standard deviation = $21.70 Sample size = 17

Q: In a random sample of 60 computers, the mean repair cost was $150 and assume that the population…

A: GivenMean(x)=150standard deviation(σ)=36sample size(n)=60confidence…

Q: Te following random sample was selected from a normal distribution: 5 9 20 12 13 16 7 15 20 7…

A: Given data is5,9,20,12,13,16,7,15,20,7sample size(n)=10