# In a server, the processor accounts for 50% of total server power, the memory system accounts for 30%, the disk accounts for 10%, and miscellaneous components account for the remaining 10%.  You have a \$500 budget to upgrade your server to make it more power-efficient.  You plan to either replace your memory module with a new memory module or your disk with a new disk. With the budget, you can either purchase a new memory module that consumes 40% less power than your old memory module, or a new disk that consumes 40% less power than the old disk.  which would you choose to purchase if you were only worried with reducing your server's power consumption?

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In a server, the processor accounts for 50% of total server power, the memory system accounts for 30%, the disk accounts for 10%, and miscellaneous components account for the remaining 10%.  You have a \$500 budget to upgrade your server to make it more power-efficient.  You plan to either replace your memory module with a new memory module or your disk with a new disk. With the budget, you can either purchase a new memory module that consumes 40% less power than your old memory module, or a new disk that consumes 40% less power than the old disk.  which would you choose to purchase if you were only worried with reducing your server's power consumption?

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Given

In a server,

Power consumption of processor = 50 % of total power

Power consumption of memory system = 30 %

Power consumption of disk = 10 %

Power consumption of miscellaneous = 10 %

Budget for power reduction = \$ 500 which can purchase either a new memory module or a new disk.

Replacement of Memory Module:

1) New memory module consumes 40% less power than the old memory module

Total Power reduction due to the replacement of the Memory Module = (Percentage reduction of the Memory Module ) x (Percentage of total server cosumption of the Memory Module)

Total power reduction using new memory module = 40 % of 30%

= 40/100 x 30 /100

= 12% reduction of total power

Replacement of Disk

New disk consumes 40% less power than the old disk

Total power reduction using new disk = 40 % of...

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