thise....docxQ4In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time college students who earn a bachelor's degree in four years or less. Find theKsample size needed to estimate that percentage. Use a 0.01 margin of error and use a confidence level of 95%. Complete parts (a) through (c) below.Z[a. Assume that nothing is known about the percentage to be estimated.n = 9604(Round up to the nearest integer.)b. Assume prior studies have shown that about 60% of full-time students earn bachelor's degrees in four years or less.AView an exampleNOn=(Round up to the nearest integer.)234F2WS2Demo Outline....docxXHcommand#Get more help -380F3ED$4CaF4RFchapt21_lecture....pdf%5V0FSTG6BAMacBook Air&FOYchapt22_lecture....pdfH&7N*F7UJ00*8ApilFB|M(- o9Kchapt23_lecture.pdfDDF9O<IH)OLcommandF10P>.AI:;Clear alloption4F11{[?+1=I▾Check answerShow All44)F12}]Xdelete1.returnshi

given data 95% confidence interval for p. E = 0.01n = ?

Answered: In a study of government financial aid…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Would you guess that people tend to buy more jeans when the weather iswarm or when it is cold? The following table shows the number of jeans (in thousands of pairs)sold in the United Kingdom in January and June for the years 1980-1985. Construct a 90%confidence interval for the difference, on average, of the number of jeans that are sold indifferent seasons each year. Year 1980. 1981. 1982. 1983. 1984. 1985Jan. 1998. 1924. 1969. 2149. 2319. 2137 June 2286 1979 2375 2369 3126 2117
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A random sample of students at a college shows that 54 of 200 students had part-time jobs. Which of the follow-ing is the correct formula for a 90% confidence interval for the proportion of all students at this college withpart-time jobs?A) 0.27 { 1.28B10.27210.732200B) 0.27 { 1.28B10.5210.52200C) 0.27 { 1.645B10.27210.732200D) 0.27 { 1.645B10.5210.52200E) 0.27 { 1.96B10.27210.732200
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A researcher is conducting a study to determine the mean trough dosage of medication for a population. Assuming a previous study was conducted for the same medication and the mean trough dose was found to be 490 mg with a standard deviation of 50 mg, calculate the margin of error for a 95% confidence interval assuming the previous study enrolled 600 individuals. E = ± 4.19 E = ± 63.57 E = ± 4.00 E = ± 0.27
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