In a survey of 1329 people. 948 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote. (a) find the probability that among 1329 randomly selected voters, at least 948 actually did vote. (b) What do the results e uf from part (a) suggest? (a) P(X2 948) =O Round to four decimal places as needed) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2948) is at least 1% OB. Some people are being less than honest because P(x2 948) is less than 5% OC. People are being honest because the probability of P(x2 948) is less than 5% OD. Some people are being less than honest because Px 2 948) is at least 1%.
In a survey of 1329 people. 948 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote. (a) find the probability that among 1329 randomly selected voters, at least 948 actually did vote. (b) What do the results e uf from part (a) suggest? (a) P(X2 948) =O Round to four decimal places as needed) (b) What does the result from part (a) suggest? O A. People are being honest because the probability of P(x2948) is at least 1% OB. Some people are being less than honest because P(x2 948) is less than 5% OC. People are being honest because the probability of P(x2 948) is less than 5% OD. Some people are being less than honest because Px 2 948) is at least 1%.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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