Question
Asked Nov 13, 2019
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In a survey of
28292829
​adults,
14121412
say they have started paying bills online in the last year.
 
Construct a​ 99% confidence interval for the population proportion. Interpret the results.
 
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Expert Answer

Step 1

Given:

Sample size = n = 2829

Favorable individual = x = 1412

Step 2
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x 1412 Sample proportion = p = = 0.51 2829 Confidence level = 0.99 The critical value for a 1-0.99 0.01 z 2.576.Using standard normal table (z-table)

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Step 3

99% confidence interval for populatio...

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Р(1 - ) Р(1 - р) ,p+zc\ n 0.499(1 - 0.499) 0.499(1-0.499) 2829 0.499+2.576 x 0.499-2.576 x 2829 (0.475,0.523)

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Math

Statistics

Hypothesis Testing

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