In a titration 2.7 cm33 of 0.100 mol dm−3−3 sodium hydroxide, NaOH solution is added to 25.0 cm33 of 0.125 mol dm−3−3 benzoic acid, C66H55COOH, solution. Calculate the pH of the resulting solution given that the pKa of benzoic acid is 4.19.
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In a titration 2.7 cm33 of 0.100 mol dm−3−3 sodium hydroxide, NaOH solution is added to 25.0 cm33 of 0.125 mol dm−3−3 benzoic acid, C66H55COOH, solution. Calculate the pH of the resulting solution given that the pKa of benzoic acid is 4.19.
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- One drop, 0.200 cm3, of 1.00 mol dm-3 of aqueous sodium hydroxide, NaOH, solution is added to 25.0 cm3 of a phosphate buffer that is 0.040 mol dm-3 in KH2PO4(aq) and 0.020 mol dm-3 in K2HPO4(aq). Calculate the resulting pH of the solution given that the second acid dissociation constant, pKa2, for phosphoric acid is 7.21.A 0.3654 g portion of pure formic acid (CH2O2, FW=46.03 g/mol, Ka=1.77 x 10-4) is dissolved in 50.00 mL of water and is titrated with 0.1086 M NaOH. What is the expected pH during this analysis when the titration is complete?Consider the titration of 100.0 mL of 0.200 mol/L ethanoic acid, HC2H3O2(aq) (Ka = 1.8 x 10-5), by 0.100 mol potassium hydroxide solution. Calculate the pH of the resulting solution when 150.0mL of potassium hydroxide solution has been added?
- The half-equivalence point of a titration occurs half way to the equivalence point, where half of the analyte has reacted to form its conjugate, and the other half still remains unreacted. If 0.480 moles of a monoprotic weak acid (Ka = 5.3 x 10-5) is titrated with NaOH, what is the pH of the solution at the half-equivalence point?If 25,0 cm3 of the NH3 (concentration 0,10 mol∙dm–3) is titrated with the HCl (concentration 0,10 mol∙dm–3), calculate the pH at the equivalence point of the titrationa) At temperature 25°C, 0.02 M hydrazine, N2H4 solution is 0.69% ionised. Calculate the i. Concentration of OH- ion ii. ionisation constant, Kb b) Calculate the mass of sodium benzoate, C6H5COONa that should be added to 500 mL of 0.2M aqueous benzoic acid, C6H5COOH solution to produce a buffer with pH 3.50?[ Ka for C6H5COOH = 6.3 x10-5] c) When a 1 x 10-3 moldm-3 solution of CaCl2 is mixed with an equal volume of a 1 x 10-3 moldm-3 solution of Na2SO4, will precipitate form? (Ksp CaSO4= 2 x 10-5) Do you mean that pH? That was all the given information the question gave.. I don't understand how to use the ionised part the most
- The weak base NH3 (concentration 0,10 mol∙dm–3) is titrated with strong acid HCl (concentration 0,050 mol∙dm–3). Without doing any calculations, explain why the pH at the equivalence point of this titration is less than 7.Sketch reasonably accurately the pH curve for the titration of 25.0 cm3 of 0.15 M Ba(OH)2(aq) with 0.22 M HCI(aq). Mark on the curve (a) the initial pH, (b) the pH at the stoichiometric point.A solution is formed by adding 6.00 grams of solid potassium acetate, KC₂H₃O₂, to 200.0 ml of 0.0240M calcium acetate, Ca(C₂H₃O₂)₂. Calculate the pH of the resulting solution. You may assume that the potassium acetate dissolve completely and that the change in volume is negligible with the addition of the solid.
- During the fermentation of wine, a buffer system consisting of tartaric acid and potassium hydrogen tartrate is produced by a biochemical reaction. Assuming that at some time the concentration of potassium hydrogen tartrate is twice that of tartaric acid, calculate the pH of the wine. The pKa of tartaric acid is 2.96.Determine the pH of a buffer solution containing 0.451 M benzoic acid (C6H5COOH) and 0.317 M sodium benzoate (C6H5COONa). Ka for benzoic acid is 6.3 × 10–5Show that the pH at the halfway point is equivalent to titration of a weak acid with a strong base equal to pKa. 0.01M
