In a workshop, there is a three-phase asynchronous motor with a power of 6 HP, an efficiency of 85%, and a power factor of 0.8. Find the capacitor capacity required for power factor correction in the workshop. (The capacitors will be connected in a delta configuration.) A new power factor of 0.95 is desired. The nominal voltage in the workshop is given as 0.4 kV. (1 HP = 0.745 kW)

In a workshop, there is a three-phase asynchronous motor with a power of 6 HP, an efficiency of 85%, and a power factor of 0.8. Find the capacitor capacity required for power factor correction in the workshop. (The capacitors will be connected in a delta configuration.) A new power factor of 0.95 is desired. The nominal voltage in the workshop is given as 0.4 kV. (1 HP = 0.745 kW)

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.21P: An industrial plant consisting primarily of induction motor loads absorbs 500 kW at 0.6 power factor...

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