In an acid base titration of Ca(OH)2 (base) and HCl (acid), if the base is solid an equilibrium reaction will occur. Using Le Chatelier’s principle, what is the shift if the solid isn’t filtered?
In an acid base titration of Ca(OH)2 (base) and HCl (acid), if the base is solid an equilibrium reaction will occur. Using Le Chatelier’s principle, what is the shift if the solid isn’t filtered?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.97PAE
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In an acid base titration of Ca(OH)2 (base) and HCl (acid), if the base is solid an equilibrium reaction will occur. Using Le Chatelier’s principle, what is the shift if the solid isn’t filtered?
![O The Importance of Filtering the Saturated Ca(OH)2 (aq) So No Solid Ca(OH)2 (s) is Present during the Titration
Ca(OH)2 (s)
Ca2+ (aq) + 2OH- (aq)
if solid not filtered out, an equilibrium can occur between the unfiltered
solid Ca(OH)2 and the aqueous Ca?• (aq) + 20H- (aq) ions
Neutralization (Titration) Reaction
If not properly
filtered. Ca(OH)2 (s)
present in solution
being titrated
Balanced eq: 2HCI(aq) + Ca(OH)2(aq) → CaCk(aq) + 2H20(1)
lonic eq: 2H*(aq) + 2CH(aq) + Ca2 (aq) + 20H-(aq) → Ca²•(aq) + 2CH(aq) + 2H2O (I)
Net lonic eq: 2H•(aq) + 2OH-(aq) → 2H¿O (I)
Effect on Volume of HCI used if Solid Ca(OH)2 (s) Impurities Present because Improperly Filtered (explained using Le Chatelier's Principle)
shift
stress
because neutralized by 0.0400 M added HCI
reaction to occur
result
• presence of Ca(OH)2 (s) impurity allows an
• as OH- (aq) ions in
Ca(OH)2 (aq) solution are neutralized, equilibrim shifts to
is added to
• more OH- (aq) ions are released from
.. .Ca(OH)2 impurity, :: additional
neutralize the extra OH- (aq) ions
• Ca(OH)2 (s) impurity continues to release OH- (ag) ions until all solid Ca(OH)2 has
• : the volume of HCI (aq) used to neutralize the solution is artificially
and calculated Ks, of Ca(OH)2 is artificially
(4 Ksp Ca(OH)2 =
. : [Ca(OH)2 (aq)] determined is artificially](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F04863a12-b1aa-4e89-b483-a79a85604772%2F82740b5b-4cbd-4453-b85c-de300fee8d0a%2F48a7hz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:O The Importance of Filtering the Saturated Ca(OH)2 (aq) So No Solid Ca(OH)2 (s) is Present during the Titration
Ca(OH)2 (s)
Ca2+ (aq) + 2OH- (aq)
if solid not filtered out, an equilibrium can occur between the unfiltered
solid Ca(OH)2 and the aqueous Ca?• (aq) + 20H- (aq) ions
Neutralization (Titration) Reaction
If not properly
filtered. Ca(OH)2 (s)
present in solution
being titrated
Balanced eq: 2HCI(aq) + Ca(OH)2(aq) → CaCk(aq) + 2H20(1)
lonic eq: 2H*(aq) + 2CH(aq) + Ca2 (aq) + 20H-(aq) → Ca²•(aq) + 2CH(aq) + 2H2O (I)
Net lonic eq: 2H•(aq) + 2OH-(aq) → 2H¿O (I)
Effect on Volume of HCI used if Solid Ca(OH)2 (s) Impurities Present because Improperly Filtered (explained using Le Chatelier's Principle)
shift
stress
because neutralized by 0.0400 M added HCI
reaction to occur
result
• presence of Ca(OH)2 (s) impurity allows an
• as OH- (aq) ions in
Ca(OH)2 (aq) solution are neutralized, equilibrim shifts to
is added to
• more OH- (aq) ions are released from
.. .Ca(OH)2 impurity, :: additional
neutralize the extra OH- (aq) ions
• Ca(OH)2 (s) impurity continues to release OH- (ag) ions until all solid Ca(OH)2 has
• : the volume of HCI (aq) used to neutralize the solution is artificially
and calculated Ks, of Ca(OH)2 is artificially
(4 Ksp Ca(OH)2 =
. : [Ca(OH)2 (aq)] determined is artificially
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