In an atomic absorption study, an unknown sample of Met*0.355. The mixture was then mixed in a 100.0 mL in a volumetric flask by puttinghad an absorbance oftogether 1.00 mL of 100.0 ppm Me4+it to mark. The 100.00 mL diluted solution had an absorbance of 0.600.with 95.0 mL of the unknown solution, and dilutingWhat is the concentration of Me4+solution?1.351 ppm0.05659 ppm0.502 ppm1.040 ppm

A question based on concentration terms that is to be accomplished.

In an atomic absorption study, an unknown sample of Me+ had an absorbance of 0.355. The mixture was then mixed in a 100.0 mL in a volumetric flask by putting together 1.00 mL of 100.0 ppm Me4+ with 95.0 mL of the unknown solution, and diluting it to mark. The 100.00 mL diluted solution had an absorbance of 0.600. What is the concentration of Me4+ solution? 1.351 ppm 0.05659 ppm 0.502 ppm 1.040 ppm

In an atomic absorption study, an unknown sample of Me+ had an absorbance of 0.355. The mixture was then mixed in a 100.0 mL in a volumetric flask by putting together 1.00 mL of 100.0 ppm Me4+ with 95.0 mL of the unknown solution, and diluting it to mark. The 100.00 mL diluted solution had an absorbance of 0.600. What is the concentration of Me4+ solution? 1.351 ppm 0.05659 ppm 0.502 ppm 1.040 ppm

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter1: Introduction

Section: Chapter Questions

Problem 1.11QAP

See similar textbooks

Similar questions

In the concentration range of 1 to 100 g/mL P, phosphate suppresses the atomic absorption of Ca in a linear manner. The absorbancc levels off, however, between 100 and 300 g/mL P. Explain. How can this effect be reduced?
1. An unknown sample of Cu2+ gave an absorbance of 0.262 in an atomic absorption analysis. Then 1.00 mL of solution containing 100.0 ppm Cu2+ was mixed with 95.0 mL of unknown, and the mixture was diluted to 100.0 mL in a volumetric flask. The absorbance of the new solution was 0.500. a) Denoting the initial unknown concentration as [Cu2+]i, write an expression for the final concentration [Cu2+]f, after dilution. Units of concentration are ppm. b) In a similar manner, write the final concentration of added standard Cu2+ designated as [S]f. c.) Find the [Cu2+]I in the unknown
To determine the content of Pb in a canned sausage, 5.00 g were weighed and after adequate treatment they were gauged to a volume of 100 mL, from there an aliquot of 2 mL was taken and brought to a volume of 250 mL. The readings of a series and of the sample were taken in an Atomic Absorption spectrophotometer, recording the following data: mg Pb/mL 0 1 2 3 4 Sample Absorbance 0.00 0.15 0.29 0.44 0.58 0.38 What is the% Pb in canned sausage?
The measurement of Li in brine (salt water) is used by geochemists to help determine the origin of this fluid in oil fields. Flame atomic absorption of Li is subject to interference by other elements. Atomic absorption of analysis of replicate sample of Li in a brine sample gave results in the table. a. Suggest a reason for the increasing apparent concentration of Li from sample 1 to 2. b. Suggest a reason for the increasing apparent concentration of Li from sample 1 to 3 c. Why do samples 4-6 give a nearly constant result? (What type of interference you think is being eliminated?
An unknown sample of Mn2+ gave an absorbance of 0.392 in an atomic absorption analysis. Then 2.00 mL of solution containing 100.0 ppm of Mn2+ (=μg/mL) was mixed with 90.0 mL of unknown, and the mixture was diluted to 100.0 mL in a volumetric flask. The absorbance of the new solution was 0.600. The blank reading for this experiment is 0.010. Denoting the initial, unknown concentration as [Mn2+]i, write an expression for the final concentration, [Mn2+]f, after dilution. Units of the concentration are ppm. In a similar manner, write the final concentration of added standard Mn2+, designated as [S]f. Find [Mn2+]i in the unknown.
Exactly 10.00-mL aliquots of a solution containing phenobarbital were measured into 50.00-mL volumetric flasks and made basic with KOH. The following volumes of a standard solution of phenobarbital containing 2.000μg/mL of phenobarbital were then introduced into each flask and the mixture was diluted to volume: 0.000, 0.500, 1.00, 1.50, 2.00 mL. The fluorescence of each of these solutions was measured with a fluorimeter, which gave values of 3.26, 4.80, 6.41, 8.02, 9.56, respectively. a. plot the data. b. derive a least squares equation for the data plotted in (a). c. find the concentration of phenobarbital from the equation in (b). d. calculate a standard deviation for the concentration obtained in (c).