We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of 56 Fe atom = mass of nucleus + 26 m. 1.0078 = mass of H atom = mass of nucleus + m, Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m.) - [26(1.0078 - ma) + 30(1.0087)]. Solve for Am. Am = 0.5289 amu

Introductory Chemistry For Today
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Author:Seager
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Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.8E
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We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass:
55.9349 = mass of 56 Fe atom = mass of nucleus + 26 m.
1.0078 = mass of H atom = mass of nucleus + me
Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m2) - [26(1.0078 - ma) + 30(1.0087)].
Solve for Am.
Am = 0.5289
amu
Transcribed Image Text:We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of 56 Fe atom = mass of nucleus + 26 m. 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m2) - [26(1.0078 - ma) + 30(1.0087)]. Solve for Am. Am = 0.5289 amu
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