In an electrochemical cell, the magnitude of the current passing between the electrodes is equal to sum of the magnitudes of each overall charge in the two electrodes divided by the time it takes for the charges to arrive at each electrode. In our case, current passes through an ionic solution. In 1.00 s, an equivalent charge of 6.49 x 103 Carrives at the negative electrode, and an equivalent charge of -8.54 x 10-3 C arrives at the positive electrode. What is the magnitude of the current passing between the two electrodes in mA? Give the answer with one decimal digit and no unit. (1 x 103 A = 1 mA)

University Physics Volume 2
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Chapter9: Current And Resistance
Section: Chapter Questions
Problem 28P: An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 3.00 amps, (a) What is the...
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In an electrochemical cell, the magnitude of the current passing between the
electrodes is equal to sum of the magnitudes of each overall charge in the two
electrodes divided by the time it takes for the charges to arrive at each electrode. In
our case, current passes through an ionic solution. In 1.00 s, an equivalent charge of
6.49 × 103 C arrives at the negative electrode, and an equivalent charge of -8.54 x
10-3 C arrives at the positive electrode. What is the magnitude of the current passing
between the two electrodes in mA?
Give the answer with one decimal digit and no unit. (1 × 10 A = 1 mA)
Transcribed Image Text:In an electrochemical cell, the magnitude of the current passing between the electrodes is equal to sum of the magnitudes of each overall charge in the two electrodes divided by the time it takes for the charges to arrive at each electrode. In our case, current passes through an ionic solution. In 1.00 s, an equivalent charge of 6.49 × 103 C arrives at the negative electrode, and an equivalent charge of -8.54 x 10-3 C arrives at the positive electrode. What is the magnitude of the current passing between the two electrodes in mA? Give the answer with one decimal digit and no unit. (1 × 10 A = 1 mA)
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