In an online blog post the presidentialapproval ratings were posted.ApprovalMarginMonthRatingof ErrorSeptember39%3.5%October42%3%The confidence interval forthe October approval rating isto

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Answered: In an online blog post the presidential…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The owner of the AGT Gas Station wishes to determine the fraction of customers who pay using a credit card or debit card. A random sample of 100 customers was surveyed and finds that 80 paid using their credit card or debit card. If you are going to construct a 99% confidence interval for the fraction of customers who paid using their credit card or debit card, what will be the value of the margin of error? a. 0.0658 b. 0.103 c. 0.0784 d. 0.0299
In a recent poll, 390 people were asked if they liked dogs, and 8% said they did. Find the margin of error of this poll, at the 99% confidence level. Recall: M.E. = z⋆⋅√ˆp(1−ˆp) / nGive your answer to three decimals
An online site presented this question, "Would the recent norovirus outbreak deter you from taking a cruise?" Among the 34 comma 43234,432 people who responded, 6868% answered "yes." Use the sample data to construct a 9090% confidence interval estimate for the proportion of the population of all people who would respond "yes" to that question. Does the confidence interval provide a good estimate of the population proportion?
1. A recent survey showed that from a sample of 500 packages delivered by a Postal Service, 480were delivered on time. a) Construct a 95% confidence interval for the proportion of all packages that are deliveredon time by the Postal Service.
he Pew Social Media Update 2014 surveyed 1,597 adult internet users on which social media websites they use. Of the users surveyed, 1,134 responded "yes" when asked if they use Facebook. Find the margin of error for the confidence interval for the population proportion with a 95% confidence level. z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576
In a recent random sampling, where 600 adults were surveyed, 16.4% indicate that they have fallen asleep watching television programs at night. Find the 98% confidence interval for the population proportion of people who sleep watching at night. Select one: A. 0.133 to 0.195 B. 0.140 to 0.189 C. 0.129 to 0.199 D. 0.137 to 0.192E. 0.143 to 0.186F. None of the above. Select letter!
In monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 8 day period had a standard error of 1.88. Find the margin of error that corresponds to a 95% confidence interval. (Round to 2 decimal places)
In a recent poll of 900 randomly selected adults, 37 % reported that they could not swim 24 yards with a margin of error of 13%. What is confidence interval for the proportion of adults who self-report that they cannot swim 24 yards? 63 < n < 603 525 < n < 691 0.37 < p < 0.50 0.24 < p < 0.50
During a laboratory analysis of human blood composition, tests are repeated and are known to be normally distributed. Fifteen tests on a given sample of blood yielded the following values 1.003 1.01 1.03 1.045 1.006 1.024 1.019 1.009 1.014 1.021 1.031 1.08 1.058 1.012 1.001 Calculate the 98% confidence interval for true composition of the blood in repeated tests of the sample.
A town council commissioned a random sample of 85 households to estimate the number of four-wheel vehicles per household in the town. The results are shown in the following frequency table. x 0 1 2 3 4 5 f 1 16 28 22 12 6 Construct a 99% confidence interval for the average number of four-wheel vehicles per household in the town.
The listed values are waiting times (in minutes) of customers at the Jefferson Valley Bank, where customers enter a single waiting line that feeds three teller windows. Construct a 99% confidence interval for the population standard deviation. 6.5 6.6 6.7 6.8 7.1 7.3 7.4 7.7 7.7 7.7 Question 7 options: [0.294, 1.086] [0.087, 1.79] [1.735, 23.589] [0.402, 1.032]
In replicate analyses, the carbohydrate content of a glycoprotein ( a protein with sugars attached to it) is found to be 12.6, 11.9, 13.0, 12.7, and 12.5 g of carbohydrate per 100 g of protein. Find the 90% confidence intervals for the carbohydrate content.

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In an online blog post the presidential approval ratings were posted. Approval Margin Month Rating of Error September 39% 3.5% October 42% 3% The confidence interval for the October approval rating is to