In C Language please.. Let's make a simple program that mirrors this beautiful idea where we ask the user for two integer inputs. The first one would represent the starting number and the second one would represent the next n integers after it.For example, if the first number inputted is 2 and the second number inputted is 3, then the output would be 3, 4, 5 because these are the next 3 integers after 2. Instructions:In the code editor, you are provided with a main() function that asks the user for two integers and calls the slowDisplay() function.This slowDisplay() function is a recursive function which should perform the functionality explained in the problem description above.This function is only partially implemented as it lacks a base case. Your task is to add the base case needed by this recursive function.Input1. Starting integer2. Number of integersOutputEnter starting integer: 2Enter how many next integers: 3345 main.c1. Slowly But Surely1 #include2by CodeChum Adminvoid slowDisplay (int, int);In life, good things take time.45- int nain(void) {int start, nextCount;Let's make a simple program that mirrors this beautiful idea7where we ask the user for two integer inputs. The first one wouldprintf("Enter starting integer: ");scanf("%d", &start);represent the starting number and the second one wouldrepresent the next n integers after it.910printf("Enter how nany next integers: ");scanf("%d", &nextCount);1112For example, if the first number inputted is 2 and the second13number inputted is 3, then the output would be 3, 4, 5 because14slowDisplay(start + 1, nextCount);these are the next 3 integers after 2.1516return 0;17 }Instructions:181. In the code editor, you are provided with a main() function19 - void slowDisplay(int start, int nextCount) I20// TODO: Add the base case hereif) {printf("%d ", start);slow Display (start + 1, nextCount - 1);that asks the user for two integers and calls the21"slowDisplay() function.22232. This slowDisplay() function is a recursive function which24should perform the functionality explained in the problem25description above.3. This function is only partially implemented as it lacks abase case. Your task is to add the base case needed bythis recursive function.Input1. Starting integer2. Number of integersOutputEnter starting integer: 2Enter how many next integers: 33-4-5

#include <stdio.h> void slowDisplay(int, int);int main(void){ int start, nextCount;…

Answered: In C Language please.. Let's make a…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In C Language please..

Let's make a simple program that mirrors this beautiful idea where we ask the user for two integer inputs. The first one would represent the starting number and the second one would represent the next n integers after it.

For example, if the first number inputted is 2 and the second number inputted is 3, then the output would be 3, 4, 5 because these are the next 3 integers after 2.

Instructions:

In the code editor, you are provided with a main() function that asks the user for two integers and calls the slowDisplay() function.
This slowDisplay() function is a recursive function which should perform the functionality explained in the problem description above.
This function is only partially implemented as it lacks a base case. Your task is to add the base case needed by this recursive function.

Input

1. Starting integer

2. Number of integers

Output

Enter starting integer: 2

Enter how many next integers: 3

main.c
1. Slowly But Surely
1 #include<stdio.h>
2
by CodeChum Admin
void slowDisplay (int, int);
In life, good things take time.
4
5- int nain(void) {
int start, nextCount;
Let's make a simple program that mirrors this beautiful idea
7
where we ask the user for two integer inputs. The first one would
printf("Enter starting integer: ");
scanf("%d", &start);
represent the starting number and the second one would
represent the next n integers after it.
9
10
printf("Enter how nany next integers: ");
scanf("%d", &nextCount);
11
12
For example, if the first number inputted is 2 and the second
13
number inputted is 3, then the output would be 3, 4, 5 because
14
slowDisplay(start + 1, nextCount);
these are the next 3 integers after 2.
15
16
return 0;
17 }
Instructions:
18
1. In the code editor, you are provided with a main() function
19 - void slowDisplay(int start, int nextCount) I
20
// TODO: Add the base case here
if) {
printf("%d ", start);
slow Display (start + 1, nextCount - 1);
that asks the user for two integers and calls the
21"
slowDisplay() function.
22
23
2. This slowDisplay() function is a recursive function which
24
should perform the functionality explained in the problem
25
description above.
3. This function is only partially implemented as it lacks a
base case. Your task is to add the base case needed by
this recursive function.
Input
1. Starting integer
2. Number of integers
Output
Enter starting integer: 2
Enter how many next integers: 3
3-4-5

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