In cattle, the gene for hornless (H) is dominant to the gene for horned (h), the gene for black (B) is dominant to that of red (b), and the gene for white face, or Hereford spotting, (S) is dominant to that for solid color (s). A cow (female) that is heterozygous for all traits is inseminated by a bull (male) of the genotype bbhhSs. What is the probability of obtaining a calf that is a black, hornless bull with Hereford spotting?

In cattle, the gene for hornless (H) is dominant to the gene for horned (h), the gene for black (B) is dominant to that of red (b), and the gene for white face, or Hereford spotting, (S) is dominant to that for solid color (s). A cow (female) that is heterozygous for all traits is inseminated by a bull (male) of the genotype bbhhSs. What is the probability of obtaining a calf that is a black, hornless bull with Hereford spotting?

Name: In cattle, the gene for hornless (H) is dominant to the gene for horn
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: In cattle, the gene for hornless (H) is dominant to the gene for horned (h), the gene forblack (B) is dominant to that of red (b), and the gene for white face, or Hereford spotting,(S) is dominant to that for solid color (s). A cow (female) that is

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter5: The Inheritance Of Complex Traits

Section: Chapter Questions

Problem 5QP: As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women....

See similar textbooks

Similar questions

In rabbits, black hair depends on a dominant allele, B, and brown hair on a recessive allele, b. short hair is due to a dominant allele, S, and long hair to a recessive allele, s. If a true-breeding black short-haired male is mated with a brown long-haired female, describe their offspring. What will be the genotypes of the offspring? If two of these f1 rabbits are mated, what phenotypes would you expect among their offspring? In what proportions?
In cattle, coat color is controlled by two codominant alleles. One allele produces a red coat, (R), and one produces a white coat, (W). A cow with heterozygous alleles will have a roan coat. In the same breed of cattle not having horns, (N), is completely dominant over the presence of horns, (n). What phenotype and genotypes would be expected from a cross between a roan, horned bull and a hornless red cow that is a carrier for the horned allele. Show the Punnett square
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the genotype of the woman's father? What is the probability that the couple's first child will be a non-freckled, normal visioned girl? What is the probability that the first two children born to the couple will be freckled and colorblind girls?
In the fictitious monster Lochnessius coolnameii, coat color is under the control of an autosomal gene, with white coat (W) dominant over black coat (w). The monster’s ability to produce horns is a sex-influenced trait, that is dominant in males but recessive in females. Let Horned = H, and hornless = h. Consider the cross of a homozygous white & horned male with a homozygous black & hornless female. What genotypes and phenotypes are expected in the F1? What genotypes and phenotypes are expected in the F2? In what ratios? Zappy is a horned white male. It was bred to the following four females, and the results are presented here: Mother Offspring Alcremie: hornless, black 1 horned white female Blissey: hornless, white 1 hornless black female Chansey: horned, black 1 horned, white female Delcattie: hornless, white 1 hornless, black male + 1 Horned white…
In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring. In horses, black is dependent upon a dominant gene, B, and chestnut upon its recessive allele, b. The trotting gait is due to a dominant gene, T, the pacing gait to its recessive allele, t. If a homozygous black pacer is mated to a homozygous chestnut trotter, what will be the appearance of the F1 generation?
In roan bulls, alleles for both red and white hair are codominant (BRBW). What is the percentage of genotype and phenotype if a roan cattle is bred to, (a) a homozygous red cow (BRBR), (b) a heterozygous white cow (BWBw).
In humans, widow's peak (H) is dominant over a continuous hairline (h), and short fingers (F) are dominant over long fingers (f). Two heterozygous individuals with widow's peak and short fingers want to have a child with continuous hairline and long fingers. Is this possible?
Skin color in humans is determined by polygenic inheritance, which means the more dominant alleles there are, the darker the skin color will be. A medium-toned skinned woman (AaBb) has a child with another medium-toned skinned man (AaBb). What is the probability of them having a very dark-toned skinned child? (Hint: the genotype is homozygous dominant)
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?
In mice, dwarfism is caused by an X-linked recessive allele, and pink coat is caused by an autosomal dominantallele (coats are normally brownish). If a dwarf femalefrom a pure line is crossed with a pink male from a pureline, what will be the phenotypic ratios in the F1 and F2 ineach sex? (Invent and define your own gene symbols.)
In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.
In rabbits, black hair is dependent on a dominant allele B, and brown upon arecessive allele b. Short-hair is due to dominant allele S and long hair to arecessive allele s. If a true-breeding black short haired male is mated with abrown, long-haired female, what will their offspring look like? What will be the genotypes of the offspring?