In each of the following problems, draw a direction field. Notice that this problem is motivated by the fact that our analytical methods for the solution of first-order differential equations do not work for these equations. Using the direction field, sketch the solutions for several possible initial values y0. Describe how solutions appear to behave as t grows, and how their behavior depends on the initial value y0. (a) y′ =ty(3−y),   y(0)=y0 (b) y′ =y(3−ty),   y(0)=y0 (c) y′ =−y(3−ty),   y(0)=y0 (d) y′ =t−1−y2,   y(0)=y0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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In each of the following problems, draw a direction field. Notice that this problem is motivated by the fact that our analytical methods for the solution of first-order differential equations do not work for these equations. Using the direction field, sketch the solutions for several possible initial values y0. Describe how solutions appear to behave as t grows, and how their behavior depends on the initial value y0.

(a) y′ =ty(3−y),   y(0)=y0

(b) y′ =y(3−ty),   y(0)=y0

(c) y′ =−y(3−ty),   y(0)=y0

(d) y′ =t−1−y2,   y(0)=y0

 

1. In each of the following problems, draw a direction field. Notice that this problem
is motivated by the fact that our analytical methods for the solution of first-order
differential equations do not work for these equations. Using the direction field, sketch
the solutions for several possible initial values yo. Describe how solutions appear to
behave as t grows, and how their behavior depends on the initial value yo.
(а) у 3 ty (3 — у),
(b) y' = y (3 – ty),
y(0) = Yo
y(0) =
(с) у 3 —у (3 — ty), у(0) %3D Уo
= Yo
(c) y'
(d) y' = t – 1– y²,
y(0) = Yo
Transcribed Image Text:1. In each of the following problems, draw a direction field. Notice that this problem is motivated by the fact that our analytical methods for the solution of first-order differential equations do not work for these equations. Using the direction field, sketch the solutions for several possible initial values yo. Describe how solutions appear to behave as t grows, and how their behavior depends on the initial value yo. (а) у 3 ty (3 — у), (b) y' = y (3 – ty), y(0) = Yo y(0) = (с) у 3 —у (3 — ty), у(0) %3D Уo = Yo (c) y' (d) y' = t – 1– y², y(0) = Yo
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