In each of the situations, choose whether or not the given assignment of probabilities to individual outcomes is legitimate. Remember, a legitimate model need not be a practically reasonable model. If the assignment is not legitimate, choose the correct reason for your answer. (a) Roll a six-sided die and record the count of spots on the up-face: P(1) = 0, P(2) = 1/6, P(3) = 1/3, P(4) = 1/3, P(5) = 1/6, P(6) = 0. This is not a legitimate model because you cannot have a probabiltiy of 0. This is not a legitimate model because one of the probabilities is greater than 1. This is a legitimate model.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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In each of the situations, choose whether or not the given assignment of probabilities to individual outcomes is
legitimate. Remember, a legitimate model need not be a practically reasonable model. If the assignment is not legitimate,
choose the correct reason for your answer.
(a) Roll a six-sided die and record the count of spots on the up-face:
P(1) = 0, P(2) = 1/6, P(3) = 1/3, P(4) = 1/3, P(5) = 1/6, P(6) = 0.
This is not a legitimate model because you cannot have a probabiltiy of 0.
This is not a legitimate model because one of the probabilities is greater than 1.
This is a legitimate model.
O This is not a legitimate model because the sum of the probabilities does not equal 1.
Transcribed Image Text:In each of the situations, choose whether or not the given assignment of probabilities to individual outcomes is legitimate. Remember, a legitimate model need not be a practically reasonable model. If the assignment is not legitimate, choose the correct reason for your answer. (a) Roll a six-sided die and record the count of spots on the up-face: P(1) = 0, P(2) = 1/6, P(3) = 1/3, P(4) = 1/3, P(5) = 1/6, P(6) = 0. This is not a legitimate model because you cannot have a probabiltiy of 0. This is not a legitimate model because one of the probabilities is greater than 1. This is a legitimate model. O This is not a legitimate model because the sum of the probabilities does not equal 1.
(b) Deal a card from a shuffled deck:
P(clubs) =
12/52, P(diamonds)
12/52, P(hearts) = 12/52, P(spades)
= 16/52.
This is a legitimate model.
This is not a legitimate model because the sum of the probabilities does not equal 1.
This is not a legitimate model because one of the probabilities is greater than 1.
This is not a legitimate model because you also need to consider the probability of the face cards.
(c) Choose a college student at random and record sex and enrollment status:
P(female full-time) = 0.56, P(female part-time) = 0.24, P(male full-time) = 0.44, P(male part-time) = 0.17.
This is a legitimate model.
This is not a legitimate model because you cannot combine the probability of sex and enrollment status.
This is not a legitimate model because one of the probabilities is greater than 1.
O This is not a legitimate model because the sum of the probabilities is greater than 1.
Transcribed Image Text:(b) Deal a card from a shuffled deck: P(clubs) = 12/52, P(diamonds) 12/52, P(hearts) = 12/52, P(spades) = 16/52. This is a legitimate model. This is not a legitimate model because the sum of the probabilities does not equal 1. This is not a legitimate model because one of the probabilities is greater than 1. This is not a legitimate model because you also need to consider the probability of the face cards. (c) Choose a college student at random and record sex and enrollment status: P(female full-time) = 0.56, P(female part-time) = 0.24, P(male full-time) = 0.44, P(male part-time) = 0.17. This is a legitimate model. This is not a legitimate model because you cannot combine the probability of sex and enrollment status. This is not a legitimate model because one of the probabilities is greater than 1. O This is not a legitimate model because the sum of the probabilities is greater than 1.
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