In Exercises 53-78, graph the piecewise-defined functions. State the domain and range in interval notation. Determine the intervals where the function is increasing, decreasing, or constant. x< 2 S-x x< -1 1 x< -1 53. f(x) 12 54. f(x) : %3D 55. f(x) = -1

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
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Author:HOUGHTON MIFFLIN HARCOURT
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Chapter8: Graphing Quadratic Functions
Section: Chapter Questions
Problem 17CT
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Vx
V x + 1
In Exercises 45-52, find the average rate of change of the function from x 1 to x = 3.
45. f(x) = x
46.) f(x)
47. f(x) = \x|
48. f(x) = 2x
49. f(x) = 1- 2x
50. f(x) = 9 – x?
51. f(x) = |5 - 2x|
52. f(x) = V – 1
In Exercises 53-78, graph the piecewise-defined functions. State the domain and range in interval notation. Determine the
intervals where the function is increasing, decreasing, or constant.
Jx x<2
(2
53. f(x)
x < -1
1 x<-1
x -1
54. f(x)
%3D
55. f(x) =
-1
x> -1
Jx? x< 2
Jx x< 0
56. f(x) =
57. f(x)
%3D
x-
58. f(x) =
x>0
59. f(x) =
S-x + 2 x< 1
60. f(x)
(2 + x x<-1
5 - 2x x < 2
61. f(x) =
%3D
x> 1
x> -1
3x - 2
x> 2
1
x< -2
-1
x< - 1
-1
x< -1
2"
62. f(x) =
63. G(x) =
-1 <x< 3
64. G(x) = {x
-1<x<
%3D
3
4 + -x
x> -2
3
x> 3
x> 3
x< -
t< 1
1<t< 2
< 1
1
-x-1
66. G(t)
67. f(x) = {x + 1
-2 <
%3D
t> 2
(-x +1 x21
- 2
so
x<1
70. G(x) =
2<x<1
69. G(x)
x> 1
1
-1<x<
Transcribed Image Text:Vx V x + 1 In Exercises 45-52, find the average rate of change of the function from x 1 to x = 3. 45. f(x) = x 46.) f(x) 47. f(x) = \x| 48. f(x) = 2x 49. f(x) = 1- 2x 50. f(x) = 9 – x? 51. f(x) = |5 - 2x| 52. f(x) = V – 1 In Exercises 53-78, graph the piecewise-defined functions. State the domain and range in interval notation. Determine the intervals where the function is increasing, decreasing, or constant. Jx x<2 (2 53. f(x) x < -1 1 x<-1 x -1 54. f(x) %3D 55. f(x) = -1 x> -1 Jx? x< 2 Jx x< 0 56. f(x) = 57. f(x) %3D x- 58. f(x) = x>0 59. f(x) = S-x + 2 x< 1 60. f(x) (2 + x x<-1 5 - 2x x < 2 61. f(x) = %3D x> 1 x> -1 3x - 2 x> 2 1 x< -2 -1 x< - 1 -1 x< -1 2" 62. f(x) = 63. G(x) = -1 <x< 3 64. G(x) = {x -1<x< %3D 3 4 + -x x> -2 3 x> 3 x> 3 x< - t< 1 1<t< 2 < 1 1 -x-1 66. G(t) 67. f(x) = {x + 1 -2 < %3D t> 2 (-x +1 x21 - 2 so x<1 70. G(x) = 2<x<1 69. G(x) x> 1 1 -1<x<
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